Pandigital primeProblem 41We shall say that an n-digit number is pandigital if it makes use of all the digits 1 ton exactly once. For ...
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2017-03-28 18:33:00
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We shall say that an n-digit number is pandigital if it makes use of all the digits 1 to n exactly once. For example, 2143 is a 4-digit pandigital and is also prime.What is the largest n-digit pandigi
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2017-07-28 12:22:00
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Pandigital prime setsProblem 118Using all of the digits 1 through 9 and concatenating them freely to form decimal integers, different ...
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2017-03-30 18:52:00
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Pandigital primeProblem 41We shall say that an n-digit number is pandigital if it makes use of all the digits 1 to n exactly once. For example, 2143 is a 4-digit pandigital and is also pri
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2022-08-11 16:57:28
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Pandigital productsProblem 32We shall say that an n-digit number is pandigital if it makes use of all the digits 1 ton exactly once; f...
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2017-03-29 06:38:00
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Pandigital productsProblem 32We sh
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2022-08-11 15:15:26
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Pandigital multiplesProblem 38Take the number 192 and multiply it by each of 1, 2, and 3:192 × 1 = 192192 × 2 = 384192 × 3 = 576By con...
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2017-03-29 22:01:00
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Pandigital multiplesProblem 38Take the number 192 and multiply it by each of 1, 2, and 3:192 × 1 = 192192 × 2 = 384192 × 3 = 576By concatenating each product we get the 1 to 9 pand
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2022-08-11 16:59:27
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Pandigital Fibonacci endsProblem 104The Fibonacci sequence is defined by the recurrence relation:Fn = Fn−1 + Fn−2, where F1 = 1 and F2 = 1.It turns out that F541, which contains 113 di
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2022-08-11 14:49:14
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import java.lang.Math.*;
import java.io.*;
public class Prime
{
public static Boolean primeNumber(long x)
{
Boolean flag = true;
if(x<4)
{
if(x==1)
flag=false;
}
else
{
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2012-02-28 21:12:13
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Pandigital Fibonacci endsProblem 104The Fibonacci sequence is defined by the recurrence relation:Fn = Fn−1 + Fn−2, where F1 = 1 and F2...
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2017-03-29 11:38:00
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r aprime) is anatural numbergreater than 1 that has no positivedivisorsother than 1 and itsel...
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2015-02-01 06:12:00
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Prime Time #include<iostream>#include<cstdio>#include<cmath>#include
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2022-08-22 21:21:51
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传送门 考场上魔改了一下线性筛，觉得要筛到 \(\frac{R}{2}\) 就没让它跑 其实正解就是这样，只不过由于接下来类似埃氏筛的过程只要筛到根号就行了 线性筛有的时候其实并不需要筛到 \(\frac{n}{2}\)，如果接下来需要枚举倍数，注意可能只需要枚举到根号就行了 发现 \(R\) 的范 ...
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2021-08-25 06:27:00
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函数函数的定义定义自己的函数，在往期的c语言学习当中，我们都是利用库里的函数，如今我们可以通过自己定义的函数，来使用例如 设置一个求解素数的函数#include <stdio.h>
int prime(int i)；
int main()
{}
int prime(int i)
{
int true=1,int t=2;
for(;t<=i-1;t++)
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2023-08-21 11:39:27
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http://poj.org/problem?id=2485很裸的最小生成树View Code 1 #include<stdio.h> 2 #include<string.h> 3 #define INF 100000 4 int w[1001][501]; 5 int visit[1001],low[1001],max; 6 void prime(int n) 7 { 8 int i,j,k; 9 memset(visit,0,sizeof(visit));10 visit[1] = 1;11 for(i = 2; i <= n ; i...
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2012-08-03 00:15:00
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http://poj.org/problem?id=3126 1 #include 2 #include 3 #include 4 using namespace std; 5 6 struct node 7 { 8 int k,step; 9 };10 11 node h[100000];12 bool p[11000];13 int x,y,tot,s[11000];14 15 void make(int n)16 {17 memset(p,0,sizeof(p));18 p[0]=1;19 p[1]=1;20 for(int i=2; i>tot...
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2013-08-21 17:10:00
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传送门题意：求区间l到r内差最小和差最大的质数对。思路：根据“若x为合数，则它在区间[2,x]
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2022-11-07 12:32:09
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此题需要使用到质因子分解的算法，可以参考以下链接：题目描述：Given any positive integer N,you are supposed to find all of prime factors,and write them in the format:N=p1^k1*p2^k2*#……*pm^km.输入格式：Each input file contains one test ca
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2019-08-30 14:38:25
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说到最小（大）生成树的典型算法当然是Prime和Kruskal了。
Kruskal比较好理解就不说了。这里主要是谈一谈Prime算法。Prime算法的核心步骤：
在带权连通图中假设V是包含所有顶点的集合， U是已经在最小生成树中的节点的集合，从图中任意某一顶点v开始，此时集合U={v}。
重复执行下述操作：
在所有u∈U,w∈V-U的边(u,w)∈E中找到一条权值最小的边，将(u,w)这条
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2023-12-19 19:21:22
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