You are playing the following Nim Game with your friend: There is a heap of stones on the table, each time one of yo be the

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"题目" c++ 二分 class Solution { public: int search(vector& nums, int target) { if(nums.size()==0) return 1; int start=0; int end = nums.size() 1; int ans

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Suppose a sorted array is rotated at some pivot unknown to you beforehand.(i.e.,0 1 2 4 5 6 7might become4 5 6 7 0 1 2).You are given a target value t...

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https://oj.leetcode.com/problems/search-in-rotated-sorted-array/ http://fisherlei.blogspot.com/2013/01/leetcode-search-in-rotated-sorted-array.html public class Solution {   &

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LeetCode Weekly Conte

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Medium！ 题目描述： 假设按照升序排序的数组在预先未知的某个点上进行了旋转。 ( 例如，数组 [0,1,2,4,5,6,7] 可能变为 [4,5,6,7,0,1,2] )。 搜索一个给定的目标值，如果数组中存在这个目标值，则返回它的索引，否则返回 -1 。 你可以假设数组中不存在重复的元素。

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"题目链接" 【题解】 会发现旋转之后，假设旋转点是i 则0..i 1是递增有序的。然后i..len 1也是递增有序的。 且nums[i..len 1]nums[0] 所以我们可以把数组分成两段了。 怎么判断我们二分中点的时候是处在哪一段中的呢? 当然就是让nums[mid]和nums[0]比较一下

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Use the most understandable method, in binary search, we can know that at least one part is sort in order. Base on that, we just neif current target is in that par...

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Suppose an array sorted in ascending order is rotated at some pivot unknown to you beforehand. You are given a target value to search. If foun

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LeetCode: 33. Search in Rotated Sorted Array题目描述Suppose an array sorted in ascending order is rotated at some pivot unknown to you beforehand.(i.e., 0 1 2 4 5 6 7 might become 4 5 6 7 0 1 2).You are g

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1. 题目 2. 解答 2.1. 方法一 直接进行二分查找，在判断查找方向的时候详细分类。 当 nums[mid] nums[mid] = nums[left]，则向左查找。 若 nums[right] target 时， 若 nums[mid] nums[right]，此时 nums[mid] 两

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There is an integer array nums sorted in ascending order (with distinct values). Prior to being passed to your function, nums is rotated at an unknown

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DescriptionSuppose an array sorted in ascending orde

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