The most fundamental way to reduce your downloads is to download only
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2023-02-16 16:19:10
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DescriptionIn order to get from one of the F (1 <= F <= 5,000) grazing fields (which are numbered 1..F) to another field, Bessie and the rest of the herd are forced to cross near the Tree of R...
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2021-07-12 17:42:26
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In this problem, a tree is an undirected graph that is connected and has no cycles. The given input is a graph that started as a tree with N nodes (wi
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2019-06-22 10:46:00
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2012-07-30 21:48:00
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题意描述：给一个N个点，M条边的有向图，和起点R，定义一条边为多余边，满足：起点R能够不经过该边到达所有N个点。问哪些边是多余的，输出多余边的条数，并按顺序输出所有多余的边1 <= N <= 100000 , 1 <= M <= 200000输入：4 6 22 12 33 13 41 44 2输出：51 3 4 5 6 ...
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2022-01-11 17:46:10
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#include <stdio.h>
#include <stack>
#include <cstring>
#include <algorithm>
using name...
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2022-06-16 00:06:54
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In this problem, a tree is an undirected graph that is connected and has no cycles.The given inalues 1, 2, …, N), with one additional
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2022-08-03 21:07:55
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题目描述：有F个牧场，1≤F≤5,000，贝茜和她的牧群经常需要从一个牧场迁移到另一个牧场。奶牛们已经厌烦老是走同一条路，所以它们想再新修一些路，这样它们从一个牧场迁移到另一个牧场时总是可以选择至少两条独立的路。现在F个牧场的任何两个牧场之间已经至少有一条路了，奶牛们需要至少有两条。给定现有的R条直接连接两个牧场的路，F-1≤R≤10,000，计算至少需要新修多少条直接连接两个牧场的路，使得任何两个牧场之间至少有两条独立的路。两条独立的路是指没有公共边的路，但可以经过同一个中间顶点。本题的意思是给定一个无向连通图，判断最少需要加多少条边，才能使得任意两点之间至少有两条相互“边独立”的道路。显然
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2021-07-29 16:19:57
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In this problem, a tree is an undirected graph that is connected and has no cycles. The given input is a graph that started as a tree with N nodes (wi
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2020-06-27 04:28:00
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POJ_3177
说实话，我现在还是不明白这个题目究竟是想让我们如何去处理问题。首先的疑惑就是如果连续输入两个1 2，1和2之间算一条路还是两条路，其次如果分别输入1 2及2 1，这时1和2之间算一条路还是两条路？
由于对上面数据的理解的不同，会用3种不同的处理方式：
①不管1 2还是2 1，就当做是1和2之间连通，也就是完全忽略题目中所说的两点之间可以有多条路，多条时只当有一条。
②两个1 2看
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2011-08-13 20:33:00
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CREATE TABLE `mytest2` ( `t1` varchar(10) DEFAULT NULL, `t2` varchar(10) DEFAULT NULL, `t3` char(10) DEFAULT NULL, `t4` varchar(10) DEFAULT NULL ) ENGINE=InnoDB DEFAULT CHARSET=latin1 ROW_FOR...
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2016-06-20 06:28:00
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In this problem, a tree is an undirected graph that is connected and has no cycles. The given input is a graph that started as a tree with N nodes (wi
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2018-08-28 20:08:00
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# 如何实现“java Remove redundant initializer”
## 引言
在Java开发过程中，我们经常会遇到一些冗余的初始化操作，这些操作可能会降低代码的可读性和性能。本文将介绍如何利用一些技巧和代码片段来删除冗余的初始化操作，从而优化代码。
## 流程概述
首先，我们先来看一下整个流程的概述，如下表所示：
| 步骤 | 描述 |
|---|---|
| 步骤1 |
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2023-08-28 05:30:13
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点双连通分量（求桥）
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2023-02-17 08:46:13
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题目In this problem, a tree is an undirected graph that is connected
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2023-03-07 15:19:10
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题目In this problem, a tree is an undirected graph that is connected and has no cycles.The given input is a graph that started as a tree with N nodes (with distinct values 1, 2, ..., N), with
文章目录写在前面背景知识已有工作已经存在的压缩方法扩展知识论文中提到的改进方向压缩的三种方式本论文压缩的写入结构本论文压缩的读结构 写在前面本文是CACHE压缩研究系列的论文解读第7篇，本论文题目是COMPRESSION ARCHITECTURE FOR BIT-WRITE REDUCTION IN NON-VOLATILE MEMORY TECHNOLOGIES，作者是来自 Universit
Redundant Paths Time Limit: 1000MS Memory Limit: 65536K Total Submissions: 16630 Accepted: 6935 Description In order to get from one of the F (1 <= F
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2021-12-31 17:49:16
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双连通图：无向图中每两个顶点都存在完全不同的两条路径 给定一个无向图，问要给它增加多少条边可以把它变成双连通图。 用tarjan缩点，可以得到一棵树，添加（叶子结点+1）/2条边可以使其成环，也就是答案~ 为了避开重边，这题用邻接矩阵存,wa了一晚上QAQ~ #include<cstdio> #in
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2020-02-15 20:13:00
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In this problem, a rooted tree is a directed graph such that, there is exactly one node (the root) for which all other nodes are descendants of this node, plus every node has exactly one parent, exce...
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2018-11-09 07:34:00
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