A message containing letters from A-Z is being encoded to numbers using the following mapping:'A' -> 1'B' -> 2...'Z' -> 26Given an encoded message containing digits, determine the total
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2022-01-17 17:12:25
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A message containing letters fromA-Zis being encoded to numbers using the following mapping:'A' -> 1'B' -> 2...'Z' -> 26Given an encoded message conta...
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2021-08-07 11:58:24
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A message containing letters fromA-Zis being encoded to numbers using the following mapping:'A' -> 1'B' -> 2...'Z' -> 26Given an encoded message conta...
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2014-11-27 16:11:00
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A message containing letters from A-Z is being encoded to numbers using the following mapping: 'A' -> 1 'B' -> 2 ... 'Z' -> 26 Given an encoded messag
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2016-07-12 02:45:00
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A message containing letters fromA-Zis being encoded to numbers using the following mapping:'A' -> 1'B' -> 2...'Z' -> 26Given an encoded message containing digits, determine the total number of ways to decode it.For example,Given encoded message"12", it cou
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2013-09-26 06:52:00
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A message containing letters from A-Z is being encoded to numbers using the following mapping: 'A' -> 1 'B' -> 2 ... 'Z' -> 26 Given an encoded messag
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2016-02-24 17:32:00
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难度:90. 非常不错的一道一维DP题目,参考了网上的做法。 看到这种求数量的,我们很容易想到动态规划来存储前面信息,然后迭代得到最后结果。我们维护的量res[i]是表示前i个数字有多少种解析的方式,接下来来想想递归式,有两种方式:第一种新加进来的数字不然就是自己比较表示一个字符,那么解析的方式有r
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2014-10-12 13:15:00
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题目链接:https://leetcode.com/problems/decode-ways/题目:A message containing letters from A-Z is being encoded to numbers using th
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2023-07-27 00:02:06
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有点意思的题目。用动态规划能够O(n)求解出来:a[i]代表子字符串string(0,i)的可能解码方式,a[i] = {a[i-1] or a[i-1]+a[i-2]}. 意思是假设string(i)不为0,至少a[i] == a[i-1],即一种解码方法是string{0,.....(i-1)}
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2021-08-06 13:56:33
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A message containing letters fromA-Zis being encoded to numbers using the following mapping:'A' -> 1'B' -> 2...'Z' -> 26Given an encoded message conta...
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2015-03-30 17:52:00
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问题描写叙述: A message containing letters from A-Z is being encoded to numbers using the following mapping: 'A' -> 1 'B' -> 2 ... 'Z' -> 26 Given an encode
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2021-12-31 14:30:47
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A message containing lettera
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2022-08-03 21:05:04
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这道题想到了用dp做,其实最后还是在缝缝补补,不过现在思路清晰一点了,这道题的难点就是0的decode 思路:首先要想明白的是,开头是0或者有连续两个0,那么decode就会失败,即return 0,想明白这点剩下的就简单了,想到用dp做的原因是,我们把假设string 是121,想象成一个一个放入,一开始容器只有一个1,之后再放入2,那么ways的增加即是新放入的2与原来的way decode中
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2023-01-11 12:07:11
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A message containing letters fromA-Zis being encoded to numbers using the following mapping:'A' -> 1'B' -> 2...'Z' -> 26Given an encoded message conta...
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2014-12-02 21:16:00
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A message containing letters fromA-Zis being encoded to numbers using the following mapping:'A' -> 1'B' -> 2...'Z' -> 26Given an encoded message conta...
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2015-02-09 13:55:00
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A message containing letters from A-Z is being encoded to numbers using the following mapping: 'A' -> 1 'B' -> 2 ... 'Z' -> 26 Given a non-empty string containing only digits, determine the total num...
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2018-11-06 07:39:00
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题目A message containing letters from A-Z is being encoded to nu
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2023-03-07 15:18:43
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A message containing letters from A-Z is being encoded to numbers using the following mapping: 'A' -> 1 'B' -> 2 ... 'Z' -> 26 Given an encoded messag
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2017-04-10 16:19:00
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A message containing letters from A-Z is being encoded to numbers using the following mapping:'A' -> 1'B' ->
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2022-05-04 17:25:23
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https://oj.leetcode.com/problems/decode-ways/ http://blog.csdn.net/linhuanmars/article/details/24570759 public class Solution {
public int numDecodings
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2015-01-05 15:27:55
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