【Leetcode】Decode Ways

题目链接：https://leetcode.com/problems/decode-ways/

题目：

A-Z

'A' -> 1 'B' -> 2 ... 'Z' -> 26

Given an encoded message containing digits, determine the total number of ways to decode it.

For example,

Given encoded message "12", it could be decoded as "AB" (1 2) or "L""12"

思路：

类似于爬楼梯题目。

算法：

public int numDecodings(String s) {  
    if (s.length() == 0)  
        return 0;  
    char sc[] = s.toCharArray();  
    if (sc[0] == '0')  
        return 0;  
    int c[] = new int[s.length()];  
    c[0] = 1;  
  
    for (int i = 1; i < sc.length; i++) {  
  
        if ((sc[i - 1] == '2' && sc[i] >= '1' && sc[i] <= '6') || (sc[i - 1] == '1' && sc[i] != '0')) {  
            if (i + 1 < sc.length && sc[i + 1] == '0') {  
                c[i] = c[i - 1];  
            } else if (i - 2 >= 0) {  
                c[i] = c[i - 1] + c[i - 2];// 类似爬楼梯题  
            } else {  
                c[i] = c[i - 1] + 1;  
            }  
        } else if (sc[i] == '0' && sc[i - 1] == '0') {  
            return 0;  
        } else if (sc[i] == '0' && sc[i - 1] > '2') {  
            return 0;  
        } else {  
            c[i] = c[i - 1];  
        }  
    }  
    return c[s.length() - 1];  
}