Least Common Multiple Problem Description The le
原创 2023-05-05 18:25:39
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Problem Description求n个数的最小公倍数。Input输入包含多个测试实例,每个测试实例的开始是一个正整数n,然后是n个
原创 2022-12-21 11:54:20
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最小公倍数的求解在最大公约数的基础上运行. 当得到a和b的最大公约数d之后, 可以马上得到a和b最小公倍数是ab / d. 由于ab在实际运算中可能会溢出,因此更恰当的写法是a / d * b.由于d是a的约数,所以a/d一定可以整除.(d是最大公因数)
转载 2019-07-30 17:31:00
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Lowest Common Multiple Plus Problem Description 求n个数的最
原创 2023-05-05 18:17:17
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DescriptionThe least common multiple (LCM) of a set of positive integers is the smallest positive integer which is divisible by all the numbers in the set. For example, the LCM of 5, 7 and 15 is 105.I
原创 2022-04-20 10:00:12
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问题 A: Least Common Multiple时间限制:1 Sec内存限制:32 MB题目描述The least
原创 2022-09-15 11:01:35
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http://acm.hdu.edu.cn/showproblem.php?pid=3092看的题解 首先 拆出的数必须是素数的次幂 假如拆出了14这样的数 他在lcm中的贡
原创 2022-06-15 20:41:22
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hdu 1019 Least Common MultipleTime Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 29850    Accepted Submission(s): 11285Problem Descri
原创 2022-12-02 00:28:24
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求多个数的lcm,水题~ int n; int gcd(int a,int b) { return b?gcd(b,a%b):a; } int lcm(int a,int b) { return a/gcd(a,b)*b; } int main() { int T; cin>>T; while(T-
转载 2021-02-12 12:21:00
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Least Common Multiple Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 44922 Accepted Submission(s
转载 2016-05-29 16:55:00
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  Least Common Multiple Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 29480    Accepted Submission(s): 11136Problem Description The least com
转载 2017-04-29 12:06:00
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问题 A: Least Common Multiple时间限制:1 Sec内存限制:32 MB提交:442解决:208
原创 2022-09-19 15:48:46
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Least Common MultipleTime Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 42382    Accepted Submission(s): 15941Problem DescriptionTh
原创 2022-08-10 10:28:14
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Least Common MultipleTime Limit: 2000/1000 MS (Java/Others)Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 11716Accepted
转载 2011-07-27 23:47:00
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Lowest Common Multiple Plus Problem Description 求n个数的最小公倍数。   Input 输入包括多个測试实例。每一个測试实例的開始是一个正整数n。然后是n个正整数。   Output 为每组測试数据输出它们的最小公倍数。每一个測试实例的输出占一行。 你能够如果最后的输出是一个32位的整数。   Sample Input
转载 2017-06-24 17:03:00
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OJ地址:https://vjudge.net/problem/HDU-2028求n个数的最小公倍数。Input输入包含多个测试实例,每个测试实例的开始是一个正整数n,然后是n个正整数。Output为每组测试数据输出它们的最小公倍数,每个测试实例的输出占一行。你可以假设最后的输出是一个32位的整数。Sample Input2 4 63 2 5 7Sample O...
原创 2019-10-16 20:35:11
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Problem Description:The least common multiple (LCM) of a set of positive integers is the smallest positive integer which is divisible by all the numbers in the set. For example, the LCM of 5, 7 and...
原创 2023-05-09 10:01:00
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题目地址:http://acm.hdu.edu.cn/showproblem.php?pid=1019 用辗转相除法求最小公倍数时要注意应该用a/y*b,若用a*b/y,则可能会数据溢出。 #include#include using namespace std;int LCM(long x,long y){ long temp; long a,b; a=x; b=...
转载 2021-08-05 14:51:02
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//其实用int就已经够用了,#include#include#include#include#include#include#include#include#include#include#include#include#includeusing namespace std;long long lcm(long long i,long long j){ i
原创 2023-07-27 18:40:38
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Problem Description The least common multiple (LCM) of a set of positive integers is the smallest positive integer which is divisible by all the numbers in the set. For example, the LCM of 5, 7 and 15
原创 2022-05-14 11:35:37
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