题目题意：将两段绳子对折连接在一起可获得的最大长度#include<iostre
原创
2023-06-27 10:16:50
40阅读
Given some segments of rope, you are supposed to chain them into one rope. Each time you may only fold two segments into loops and chain them into one
转载
2020-04-22 16:57:00
93阅读
2评论
1125 Chain the Ropes （25 point(s)）Given some segments of rope, you are supposed to chain them into one rope. Each time you may only fold two segments into loops and chain them into one piece
原创
2022-09-15 10:55:51
71阅读
Given some segments of rope, you are supposed to chain them into one rope. Each time you may only fold two segments into loops and chain them into one
转载
2018-03-02 16:10:00
42阅读
Given some segments of rope, you are supposed to chain them into one rope. Each time you may only fold two segments into loops and chain them into one
转载
2019-02-28 21:59:00
71阅读
#include<iostream>#include<stdio.h>#include<stdlib.h>#include<math.h>#include<string.h>#include<algorithm> #include<map>#include<vector>#inclu...
原创
2022-07-14 10:24:24
23阅读
1125. Chain the Ropes (25)时间限制200 ms内存限制65536 kB代码长度限制16000 B判题程序Standard作者CHEN, YueGiven s
原创
2022-11-10 01:20:20
26阅读
1125 Chain the Ropes (25 分)Given some segments of rope, you are supposed to chain them into one rope. Each time you may only fold two segments into loops and chain them into one piece, as shown by the figure. The resulting chain will be treated as another
原创
2021-07-07 10:53:43
77阅读
1125 Chain the Ropes （25 point(s)）Given some segments of rope, you are supposed to chain them into one ro
原创
2023-05-18 14:21:45
105阅读
PAT (Advanced Level) Practice 1125 Chain the Ropes (25 分) 凌宸1642 题目描述： Given some segments of rope, you are supposed to chain them into one rope. Each ...
转载
2021-08-15 13:59:00
103阅读
2评论
写在前面思路分析越早加入段，对折次数越多。所以希望得到结绳最大长度，必须
原创
2022-08-23 16:16:31
23阅读
目录1，题目描述题目大意2，思路3，AC代码4，解题过程第一搏第二搏第三搏1，题目描述Sample
原创
2022-10-27 16:03:52
129阅读
UVA_10985
L和R的间距能拉多远是取决于L与R之间的最短路，因此，水平悬挂的绳一定是L和R之间最短路的一个部分。
而水平的Ring一定满足到L与R的距离和是L与R之间最短路的长度，因此我们可以先把所有水平的Ring找出来，符合要求的线一定是这些水平Ring之间的连线，但水平Ring之间的连线不一定符合要求（当两个Ring位于同一位置且恰好两者之间有一条连线，这条连线就不符合要求）。
因此，
转载
2011-10-17 02:29:00
25阅读
Problem D Rings'n'Ropes
Time Limit: 3 seconds
"Well, that seems to be the situation. But, I don't want that, and you don't want that, and Ringo here definitely doesn't want that."
转载
2013-12-03 10:37:00
53阅读
2评论
1. 联合概率（joint distribution）的链式法则
基于链式法则的 explicit formula：
p(x1:n)===p(x)p(x1)∏i=2np(xi|x1,…,xi−1)∏i=1np(xi|x1,…,xi−1)
等式左端表示联合概率分布，joint distribution，所谓联合概率表示的事件同时发生的概率，如 p(x3|x1,x2)，的实际含义恰在于，事件
转载
2017-04-20 22:09:00
307阅读
1. 联合概率（joint distribution）的链式法则基于链式法则的 explicit formula：p(x1:n)===p(x)p(x1)∏i=2np(xi|x1,…,xi−1)∏i=1np(xi|x1,…,xi−1)等式左端表示联合概率分布，joint distribution，所谓联合概率表示的事件同时发生的概率，如 p(x3|x1,x2)，的实际含义恰在于，事件 x1 和事件
转载
2017-04-20 22:09:00
253阅读
2评论
On ERP sales order, the check is execute at function module RV_MATERIAL_STATUS_CHECK, it will check X-Distribution Chain and Distribution Chain at the same time, as a result it will have same effect o...
原创
2021-07-15 16:41:37
505阅读
On ERP sales order, the check is execute at function module RV_MATERIAL_STATUS_CHECK, it will check X-Distribution Chain and Distribution Chain at the same time, as a result it will have same effect o
原创
2022-04-21 16:48:10
230阅读
题目传送门 1 /* 2 我校oj的源题，看懂题意就很水，贴出来省的再敲:) 3 */ 4 #include 5 #include 6 #include 7 using namespace std; 8 9 const int MAXN = 1e3 + 10;10 const int...
转载
2015-06-06 16:33:00
76阅读
题目大意：有N个戒指，M条线将N个戒指给连接了起来，线的长度是相等的，一条线只有左右两端有戒指，现在要求取出两个戒指，在线不断的情况下，将戒指往左右两边拉，问在同一水平高度的线最多有几条解题思路：假设每条线的长度为1。两个点之间的线的数量在同一水平高度最多的情况，肯定是距离最短的时候，因为再加长的话，最短状态下的线会断。现在的难题是要统计在两点间有多少的线，将两点间最短距离的状况下所经过的点都
原创
2023-04-07 10:39:43
84阅读
