Tempter of the Bone Problem Description The doggie found a bone in an ancient maze, which fascinated him a lot. However, when he picked it up, the maz
转载 2016-11-15 17:55:00
56阅读
2评论
Problem DescriptionThe doggiefound a bone in an ancient maze, which fascinated him a lot.However, when he picked it up, the maze began to shake, an...
转载 2016-04-01 09:17:00
51阅读
2评论
long long w[1100]; int main() { int t; cin>>t; while(t--) { memset(f,0,sizeof(f)); int n,m; cin>>n>>m; for(int i=1;i<=n;i++)
原创 2022-11-07 15:19:08
70阅读
http://acm.hdu.edu.cn/showproblem.php?pid=2602 Bone Collector 递归做法   //Bone Collector   递归做法  #include<stdio.h>  #define N 1005  #define&nbsp
原创 2011-08-06 09:02:21
513阅读
DescriptionMany years ago , in Teddy’s hometown there was a man who was called “Bone Collector”. This man like to collect varies of bones , such as do...
原创 2021-08-04 11:12:47
74阅读
Problem DescriptionThe doggiefound a bone in an ancient maze, which fascinated him a lot.However, when he picked it up, the maze began to shake, an...
转载 2016-04-01 09:17:00
56阅读
2评论
Problem DescriptionThe doggie found a bone in an ancient maze, which
原创 2022-11-30 09:57:36
52阅读
本题要求在指定时间点到达目的地, 一开始用的广搜, 但是搜出的是最短路径, 理解错题意了... 使用深搜, 只要搜索到一个能在指定时间点到达目的地的路径就返回(由于深搜可能会爆栈, 所以要用到奇偶剪枝) 奇偶剪枝结论:若 t-[abs(ex-sx)+abs(ey-sy)] 结果为非偶数(奇数),则无
转载 2019-09-23 16:40:00
23阅读
2评论
Tempter of the BoneTime Limit : 2000/1000ms (Java/Other)Memory Limit : 65536/32768K (Java/Other)Total Submission(s) : 3Accepted Submission(s) : 1Font:Times New Roman|Verdana|GeorgiaFont Size:←→Problem DescriptionThe doggie found a bone in an ancient maze, which fascinated him a lot. However, when he
转载 2013-03-20 16:27:00
63阅读
2评论
Tempter of the BoneTime Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768him a lot. However, when he picked it up, the maze began to sha
原创 2022-03-18 14:43:07
20阅读
题目地址:点击打开链接思路:普通回溯要超时,用到奇偶减枝,网上资料比较多,说我的理解:判断起始点到终点的最短步数,无论偏移几格,偏移的步数一定为偶数,所以最短走的路和要走的路奇偶性相同,所以他们的和或差就相同,不相同就可以直接回溯;AC代码:#include#include#include#includeusing namespace std;char lol[8][8]
原创 2022-08-04 09:03:18
15阅读
Problem DescriptionThe doggie found a bone in an ancient maze, which fascinated him a lot. However, when he pic
原创 2022-11-10 00:00:27
55阅读
HDU_1010     这个题目由于block只能经过一次,那么我们在搜索的过程中就必须要记录各个block的状态了,而且这个题目跟最短的距离并无直接联系,如果使用bfs的话还必须要将所有的路径搜到不能走或者时间到T的时候,无论是空间还是时间上都耗费很大,所以我们选用好写的dfs就可以了。     此外这个题目还有一个预先初步判断初始状态是否可达,原理就像是把格子染成国际棋盘一样,dog在奇数的
转载 2012-03-02 20:54:00
33阅读
2评论
#include#include#includeusing namespace std;#define Max 9struct Node{ int x,y; char c; bool flag;} map[Max][Max],st,en;int f[4][2]= {0,1,0,-1,1,0,-1,0};int n,m,t;//int step;int myfabs(int x){ if(xt) return 0; if((myfabs(x-en.x)+myfabs(y-en.y)+t-step)%2)//剪枝 return 0; ...
转载 2013-09-12 22:09:00
60阅读
Bone Collector Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 66304 Accepted Submission(s): 2766
转载 2017-08-26 15:04:00
60阅读
2评论
Tempter of the Bone Time Limit: 2 Seconds Memory Limit: 65536 KB The doggie found a bone in an ancient maze, which fascinated him a lot. ...
转载 2016-05-18 00:12:00
58阅读
2评论
题目链接:传送门题面: Bone CollectorProblem DescriptionMany ye
原创 2022-10-25 16:37:16
111阅读
题目:http://acm.hdu.edu.cn/showproblem.php?pid=2602#include#include#define M 1010int T;int N;//骨头数量int V;//背包容
原创 2022-08-22 17:48:06
59阅读
题目链接:Bone Collector01背包裸题
原创 2022-08-31 10:35:43
65阅读
二位数组做法;#include#include#define M 1009typede
原创 2022-08-06 00:01:33
44阅读
  • 1
  • 2
  • 3
  • 4
  • 5