Tree-Tac-Toe_51CTO博客

CF1110G - Tree-Tac-Toe 题解

首切 3000+ 祭第一次独自切掉 3100（前纪录是 2900），是在模拟赛里面做出来的，写个题解纪念一下。首先 Black 一定是不会赢的，这个感性理解一下就可以了。然后对于这种像个智力题一样的博弈，一般都是分成各种 corner case 讨论掉以覆盖掉所有情况。我们先不管有已经被涂了的点，那只会让 White 更牛逼。显而易见的是，有四度点的话 White 必胜。于是下面从讨论最大度数为

Tree-Tac-Toe

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mb601cfae7df0aa

2021-03-09 17:56:04

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2评论

Tic Tac Toe

More Games at arcadecabin.com | Cool Generators

职场

游戏

休闲

转载精选

spirit9

2008-11-08 12:12:29

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Design Tic-Tac Toe

Hint: 看了hint之后想到：既然用数组的话，一行一列都是一个element来代表，估计这个element是要用sum了，那么，能不能用sum来代表一行，使它有且只有一种可能，全部是player1完成的/全部是Player2；所以想到了是Player1就+1，是player2就-1，看最后sum

Leetcode

Design

数组

其他

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mb5fdb0a6739180

2016-12-15 10:59:00

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react Game: Tic Tac Toe

* Board.jsimport React from 'react';class Board extends React.Component { renderSquare(i) { return ( <Square value={this.props.squares[i]} ...

react

sed

css

html

ubuntu

原创

mzh9112

2021-08-13 10:00:14

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POJ 2361 Tic Tac Toe

题目

#include

#define

i++

原创

wx634d08b5232a4

2022-10-20 11:09:43

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[BUUCTF][BSidesCF 2019]Pick Tac Toe

在网页源代码当中发现因此我们只需要按顺序post三个value来战胜ai，我分别是ul,c,bl

其它

原创

Y4tacker

2022-11-06 16:58:45

167阅读

348. Design Tic-Tac-Toe

Design a Tic-tac-toe game that is played between two players on a n x n grid. You may assume the following rules: A move is guaranteed to be valid and

自增

一维数组

html

JAVA

转载

mob6047570233c4

2016-07-27 21:01:00

149阅读

2评论

圈叉棋（Tic-Tac-Toe）

圈叉棋

休闲游戏

javascript

原创

qq61b6d41d3f9e6

2021-12-27 14:47:02

2616阅读

3C - Tic-tac-toe

题目本身不难，但是细节很多题意：给你一个井字棋盘，要求你判断其状态思路：按照规则判断即可，难的是不合法状态考虑不全，先手和后手赢的时候，两个人棋盘上的棋子关系是固定的。代码如下char g[5][5]; bool flag = false; //判断是否合法 void judge(char c, int &win) { if(c == 'X') { if(win == 2) fl

Tic-tac-toe

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mb6063e380e7d47

2021-04-03 21:00:28

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794. Valid Tic-Tac-Toe State

A Tic-Tac-Toe board is given as a string array board. Return True if and onl

leetcode-java

原创

wx62ea2466cca9a

2022-08-03 17:07:55

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（fzu） Problem L Tic-Tac-Toe（水）

Problem Description Kim likes to play Tic-Tac-Toe. Given a current state, and now Kim is going to take his next move. Please tell Kim if he can win the game in next 2 moves if both player are clever

ACM_训练赛

ACM_简单题

原创

fzhiy

2021-07-06 14:03:03

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【codeforces 3C】Tic-tac-toe

【链接】 "我是链接,点我呀:)" 【题意】题意【题解】写一个函数判断当前局面是否有人赢。然后枚举上一个人的棋子下在哪个地方。然后把他撤回看看撤回前是不是没人赢然后没撤回之前是不是有人赢了。如果是的话那么就是满足要求的啦吸吸吸【代码】 java include define ll

i++

ios

#define

#include

c++

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mb5fe32930661bd

2019-04-02 15:41:00

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leetcode-348-Design Tic-Tac-Toe

error:do not know what is move means,use row array, col array, diag, anti_diag to record current situation. Assign 1 if player is 1, and -1 if player is 2

系统

原创

zem_nezer

2023-08-23 09:04:55

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LeetCode "Design Tic-Tac-Toe"

We don't have to keep a complete chess board.. just counters!

学习

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mob604756e6cfe5

2016-05-07 14:05:00

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2评论

[LeetCode] 348. Design Tic-Tac-Toe

Assume the following rules are for the tic-tac-toe game on an n x n board between two players: A move is guaranteed to be valid and is placed on an em

leetcode

java

design

井字棋

赋值

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mb5ff5901795aaf

2021-03-15 06:33:00

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L - Tic-Tac-Toe FZU - 2283 （思维）

题目链接： L - Tic-Tac-Toe FZU - 2283 题目大意：两个人下棋，一共是三步棋，第一个人下一步，第二个人下一步，第三个人下一步，然后问你在两个人在都足够聪明的条件下，第一个人能否获胜？（获胜的前提，其中一个人的三个棋子连成了一条线）。参考博客： Tic-Tac-Toe FZU

i++

#include

ios

c代码

csdn博客

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mb5fd869d1d8388

2019-04-12 16:48:00

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2评论

794. Valid Tic-Tac-Toe State

A Tic-Tac-Toe board is given as a string array board. Return True if and only if it is possible to reach this board position during the course of a va

java

编程

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mob604756ff6c49

2019-05-17 17:37:00

90阅读

2评论

1275. Find Winner on a Tic Tac Toe Game

Tic-tac-toe is played by two players A and B on a 3 x 3 grid. Here are the rules of Tic-Tac-Toe: Players take turns placing characters into empty squa

i++

it

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mob604756fa96d7

2019-12-03 15:14:00

118阅读

2评论

LeetCode 348. Design Tic-Tac-Toe

原题链接在这里：https://leetcode.com/problems/design-tic-tac-toe/ 题目： Design a Tic-tac-toe game that is played between two players on a n x n grid. You may as

LeetCode

Design

java

JAVA

转载

mb5fcdf3fd1fd25

2019-12-19 12:41:00

106阅读

2评论

C2. Errich-Tac-Toe (Hard Version)

题目链接题意：构造一种方式使得X和O不能出现横着或者竖着的三个情况，要求操作不超过k，k为O和X的总和.思路：把这个图变成三分图，可以发现横着或者竖着连续的，他们横纵坐标相加%3都不同。我们用个计数器来记录每个位置%3 X或者O出现的次数，我们只需要改变一个位置，就可以使得不出现连续的情况，但是如果O和X出现的最小值都是某个数的时候就可能出现改完X使得O出现连续，那么我们只需要取两个不同的模的最小值就行了，可以证明这样操作的数小于等于k/3。#include<bits/stdc++.h&g.

codeforces

思维

编程题目

原创

black_hole6

2021-07-09 14:34:46

177阅读

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