There are N children standing in a line. Each child is assigned a rating value. You are giving candies to these children subjected to the following re
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2016-07-21 05:52:00
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There areNchildren standing in a line. Each child is assigned a rating value.You are giving candies to these children subjected to the following requirements:Each child must have at least one candy.Children with a higher rating get more candies than their neighbors.What is the minimum candies you mu
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2013-10-03 08:55:00
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动态规划：There areNchildren standing in a line. Each child is assigned a rating value.You are giving candies to these children subjected to the following ...
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2014-11-26 22:46:00
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There areNchildren standing in a line. Each child is assigned a rating value.You are giving candies to these children subjected to the following requi...
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2014-07-04 10:32:00
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There areNchildren standing in a line. Each child is assigned a rating value.You are giving candies to these children subjected to the following requi...
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2014-07-08 22:17:00
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/* */#include#include//#include#include using namespace std;#define STOP system("pause");#if 1class Solution {public: int candy(vector &ratings) { i...
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2015-10-14 19:41:00
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There areNchildren standing in a line. Each child is assigned a rating value.You are giving candies to these children subjected to the following requi...
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2014-06-25 15:58:00
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比赛总结 题目题意：有f种口味的糖果，现在要把每颗糖果分到一些packs里面去。packs分两种：flavored pack：只有一种口味。variety pack：每种口味都有。求满足下列要求的分法有多少种：1、每个pack至少有两颗糖果。2、所有pack的糖果数相同。3、variety pack 里每种口味的糖果数量相同。4、至少一个variety pack。5、每种口味至少一个flavored pack。 题解：设一个pack 的糖果数为lim。由3知lim是f的倍数。并且去掉variety packs后，剩下的每种糖果间的差值还跟原来一样，要将它们分完必须都是lim的倍数，也就是差值也
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2013-09-02 18:24:00
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https://oj.leetcode.com/problems/candy//***There are N children standing in a line. Each child is assigned a rating value.*You are giving candies to t...
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2015-07-03 15:13:00
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Question There are N children standing in a line. Each child is assigned a rating value.You are giving candies to these children subjected to the following requirements:Each child must have at least
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2023-02-02 14:53:09
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贪心法 复杂度 时间 O(N) 空间 O(N) 思路 典型的贪心法，如果一个孩子比另一个孩子的分高，我们只多给1块糖。我们可以先从左往右遍历，确保每个孩子根他左边的孩子相比，如果分高，则糖要多1个，如果分比左边低，就只给一颗。然后我们再从右往左遍历，确保每个孩子跟他右边的孩子相比，如果分高则糖至少多
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2014-09-20 13:18:00
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原题链接在这里：https://leetcode.com/problems/candy/ There are N children standing in a line. Each child is assigned a rating value. You are giving candies to
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2015-11-05 07:52:00
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题解： 由题意得需要运用： C(m,n)=exp(logC(m,n))f[0]=0;for(int i=1; i#includedouble f[400005];double logC(int m,int n){ return f[m]-f[n]-f[m-n];}int main(){ f[0]=0; int test=0,n; double p,q,ans; for(int i=1;i<=400002;i++) f[i]=f[i-1]+log(i*1.0); while(scanf("%d %lf",&n,&p)!=EOF) { ...
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2013-10-30 20:52:00
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There are N children standing in a line. Each child is assigned a rating value. You are giving candies to these children subjected to the following re
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2017-06-08 17:56:00
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目录?问题描述?解题思路?解题代码?问题描述题目描述WCB某天买了非常多的糖果并把它们分成N份，依次分
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2022-08-08 20:43:21
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if(ratings.empty())return 0;
else if(ratings.size()==1)return 1;
int sum=0;
int up_Cnt=0;
...
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2023-01-11 12:09:13
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https://leetcode.com/problems/candy/注意思路 1. 首先为每一个孩子分配1个糖果 记当前孩子序号为i，糖果数为
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2023-06-29 09:57:26
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源向每个小孩连边，容量是该小孩的初始糖数； 每个小孩向汇连边，容量是糖的平均数； 每个小孩想相邻的格子各连一条边，容量是1. 把图建
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2023-09-15 09:46:32
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"LeetCode 135 Candy" 思路： 将数组排序。然后根据值从小到大，在数组中依次标记值。 c++
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2022-10-18 13:57:43
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