json.dumps(data,ensure_ascii=False,indent=4,sort_keys=True,skipkeys=True,separators=(',',': ')) try: b(1,0) except Exception as e: logging.exception(s ...
转载 2021-04-23 18:30:00
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package ersatz; import java.io.FileNotFoundException; public class Ersatz { public static void main(String[] args) throws FileNotFoundException { try ...
转载 2021-07-15 11:36:00
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传送门Finally, a basketball court has been opened in SIS, so Demid has decided to hold a basketball exe
原创 2022-11-07 13:46:03
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It is important for parents to establish an exercise routine for thei
原创 2022-08-04 13:06:34
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 show status like 'innodb_row_lock%';select table_name,table_rows from information_schema.tables where table_schema='courier' order by table_rows desc;show table status from mysql where comment='view'
转载 2021-04-27 09:55:31
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Rails为支持REST开发提供的3个工具: 1. map.resources map.connect '', :controller=>'home', :action=>'welcome' map.connect '/post/:id', :controller=>'post', :action=>'show' map.connect '/weather/:yea
原创 2008-09-15 09:01:08
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学号与姓名分别对应如下: 1,2,3,4,5,6,7 赵一,钱二,孙三,李四,周五,吴六,郑七 作一程序,接收学号为参数,打印出学号对应的姓名 .<!DOCTYPE html><html><head> <title>04</title></head><body> <form ac
原创 2017-10-25 08:24:13
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fun main(args: Array<String>) { val ipToCount = mutableMapOf<String, Int>() File("src/ips.txt").forEachLine { val previous = ipToCount.getOrDefault(it
转载 2020-10-14 15:26:00
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This is one of the most daunting problems I have ever solved in my life. Another one with a similar complex nature that comes in to my mind is the extended regular expression parser I implemented. For the latter I still not 100% sure if it works perfectly as expected, it passed some typical tests th Read More
转载 2013-06-01 20:30:00
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问题描述Wodex opened the door successfully. At the same time, horn sounded: If you are not clever, the game will be so Wodex came in with his par
原创 2023-04-24 09:31:51
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输入: 拓扑文件,格式如下。注意: 指定:主机名、交换机名、链路名 + 流表项文件名(对应交换机) 无需指定:IP地址、MAC地址(run_exercise.py生成) 字典格式:key:"hosts",value:是一个list { "hosts": [ "h1", "h2", "h3" ], " ...
转载 2021-09-08 10:20:00
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对于一个排列$p_{i}$,假设循环长度依次为$x_{1},x_{2},...,x_{m}$,那么所需步数即${\rm lcm}_{i=1}^{m}x_{i}$ 由于是乘积,因此可以枚举素数$p$,并统计其的次数(注意这是对$\varphi(M)=M-1$取模) 类似于$E(X)=\sum_{i\g ...
转载 2021-09-22 14:13:00
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TRAFFIC ANALYSIS EXERCISE - Ransomer、
原创 2022-09-20 22:06:36
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Right postureLeave your seat every hourCardio exercise 30 minutesLower back exercisePhysiotherapy: Lower Back Pain - Part 1 From <https://www.youtube.
原创 2022-03-22 17:35:09
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(1)如何判断两个单链表相交,以及时间复杂度的分析;(2)如何判断单链表是不是有环(4)TCP和UDP的区别;
转载 2022-09-06 09:36:41
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题目DescriptionFarmer John(又)想到了一个新的奶牛晨练方案! 如同之前,Farmer John 的 N 头奶牛( 1 ≤ N ≤ 7500 )站成一排。对于 1 ≤ i ≤ N 的每一个 i ,从左往右第 i 头奶牛的编号为 i 。他告诉她们重复以下步骤,直到奶牛们与她们开始时的顺序相同。给定长为 N 的一个排列 A ,奶牛们改变她们的顺序,使得在改变之前从左往右第 i ...
原创 2021-07-13 13:57:16
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The spread of international commerce has taken English along with it. Leadership skills are also developed by learning to organize and conduct meeting
转载 2018-01-02 09:58:00
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In order to study the convergence of $(1+\frac{1}{n})^n$ to$e$,consider the sequences \begin{equation} a_n=(1+\frac{1}{n})^n~~~\mbox{and}~~~b_n=(...
转载 2012-11-12 20:18:00
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Python Quiz & Python Exercise
转载 2020-08-04 16:25:00
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Description有N只兔子站在数轴上。为了方便,将这些兔子标号为1…N。第i只兔子的初始位置为xi。现在这些兔子会按照下面的规则做若干套体操。每一套体操由M次跳跃组成;在第j次跳跃的时候,第aj(2≤aj≤N−1)只兔子会等概率随机选择第aj−1或aj+1只兔子中的一只(不妨设选择了第x只兔子),然后跳当前位置到关于第x只兔子对称的点。这些兔子会按顺序做K套相同的体操。现在请你求出,每...
原创 2021-07-13 14:51:33
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