UVA-550

题意

输入进制数n,第一个乘数的最后一位m,第二个乘数k,乘法的结果为mk,

mk的第一位是m,求此时mk的长度

#include<iostream>
#include <stdio.h>
#include <memory.h>
using namespace std;

int main()
{
	
	int base, end, m;
	while (cin >> base >> end >> m)
	{
		int total = 0;
		int k, dx;
		dx = 0;
		k = end;
		while (1)
		{
			total++;
			end = end * m + dx;
			dx = end / base;
			if(k == end && dx == 0)
			{
				break;
			}
			end = end % base;
		}
		cout << total << endl;

	}
	return 0;
}