190 - Circle Through Three PointsTime limit: 3.000 secondshttp://uva.onlinejudge.org/index.php?option=onlinejudge&page=show_problem&problem=126The solution is to be printed as an equation of
这次推荐的题目比上次难了，也复杂多了。PS：下面的OJ之中，CII是指ACM-ICPC Live Archive ，网址是：http://cii-judge.baylor.edu/一。基础题目1.1 有固定算法的题目A， 最近点对问题最近点对问题的算法基于扫描线算法。ZOJ 2107 Quoit Design 典型最近点对问题POJ
10387 - BilliardTime limit: 3.000 secondshttp://uva.onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=101&page=show_problem&problem=1328In a billiard table with horizontal sid
10250 - The Other Two TreesTime limit: 3.000 secondshttp://uva.onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=101&page=show_problem&problem=1191You have a quadrilateral s
http://poj.org/problem?id=1127/*16ms,376KB*/ #include<cstdio> #include<cstring> struct P { int x, y; P(int x = 0, int y = 0): x(x), y(y) {} P operator + (P p) { return P(x + p.x, y
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