需求
统计某游戏平台新用户渠道来源
日志格式如下:
1. Jul 23 0:00:47 [info] {SPR}gjzq{SPR}20130723000047{SPR}85493108{SPR}S1{SPR}{SPR}360wan-2j-reg{SPR}58.240.209.78{SPR}
分析
问题的关键在于先找出新用户
新用户:仅在7月份登陆过平台的用户为新用户
依据map/reduce思想,可以按照如下方式找出新用户:
- 假如某用户在某月份出现过,则(qid,year,month)=1
- 按qid汇总该用户出现过的月数,即构建(qid,count(year,month))对
- 新用户的count(year,month)=1,且(year,month)=(2013,07).
找出新用户的来源渠道
来源渠道:新用户在201307可能多次登录平台,需要找出最早登陆平台所属渠道
分两步来做:
- 找出新用户所有登陆记录(qid,logintime,src)
- 针对同一qid找出logintime最小时的src
实现
- 数据准备
1)建表
1. create table if not exists glogin_daily (year int,month int,day int,hour int,logintime string,qid int,gkey string,skey string,loginip string,registsrc string,loginfrom string) partitioned by
依据日志内容及所关心的信息创建表格,按天组织分区
2 ) 数据导入
因日志文件存在于多处,我们先将日志汇总到一临时目录,创建临时外部表将数据加载进hive,然后通过正则匹配的方式分隔出各字段。(内部表只能load单文件,通过这种方式可以load文件夹)
1. echo "==== load data into tmp table $TMP_TABLE ==="
2. "create external table $TMP_TABLE (info string) location '${TMP_DIR}';"
3. "==== M/R ==="
4. 1-4`
5. 5-6`
6. 7-8`
7. "${CURR_YEAR}-${CURR_MONTH}-${CURR_DAY}"
8. "add file ${SCRIPT_PATH}/${MAP_SCRIPT_FILE};set hive.exec.dynamic.partition=true;insert overwrite table glogin_daily partition (dt='${dt}') select transform (t.i) using '$MAP_SCRIPT_PARSER ./${MAP_SCRIPT_FILE}' as (y,m,d,h,t,q,g,s,ip,src,f) from (select info as i from ${TMP_TABLE}) t;"
其中filter_login.php:
1. $fr=fopen("php://stdin","r");
2. $month_dict = array(
3. 'Jan'
4. 'Feb'
5. 'Mar'
6. 'Apr'
7. 'May'
8. 'Jun'
9. 'Jul'
10. 'Aug'
11. 'Sep'
12. 'Oct'
13. 'Nov'
14. 'Dec'
15. );
16. while(!feof($fr))
17. {
18. $input = fgets($fr,256);
19. $input = rtrim($input);
20. //Jul 23 0:00:00 [info] {SPR}xxj{SPR}20130723000000{SPR}245396389{SPR}S9{SPR}iwan-ng-mnsg{SPR}cl-reg-xxj0if{SPR}221.5.67.136{SPR}
21. if(preg_match("/([^ ]+) +(\d+) (\d+):.*\{SPR\}([^\{]*)\{SPR\}(\d+)\{SPR\}(\d+)\{SPR\}([^\{]*)\{SPR\}([^\{]*)\{SPR\}(([^\{]*)\{SPR\}([^\{]*)\{SPR\})?/",$input,$matches))
22. {
23. $year = substr($matches[5],0,4);
24. echo $year."\t".$month_dict[$matches[1]]."\t".$matches[2]."\t".$matches[3]."\t".$matches[5]."\t".$matches[6]."\t".$matches[4]."\t".$matches[7]."\t".$matches[11]."\t".$matches[8]."\t".$matches[10]."\n";
25. }
26. }
27. fclose ($fr);
2.找出新用户
1)用户登陆平台记录按月消重汇总
1. create table distinct_login_monthly_tmp_07 as select qid,year,month from glogin_daily group by qid,year,month;
2)用户登陆平台月数
1. create table login_stat_monthly_tmp_07 as select qid,count(1) as c from distinct_login_monthly_tmp_07 where year<2013 or (year=2013 and month<=7) group by
平台级新用户:
1)找出登陆月数为1的用户;
2.判断这些用户是否在7月份出现,如果有出现,找出登陆所有src
1. create table new_player_monthly_07 as select distinct a.qid,b.src,b.logintime from (select qid from login_stat_monthly_tmp_07 where c=1) a join (select qid,loginfrom as src,logintime from glogin_daily where month=7 and year=2013) b on
找出最早登陆的src:
1. add
2. create table new_player_src_07 as select transform (t.qid,t.src,t.logintime) using 'php ./get_player_src.php' as (qid,src,logintime) from (select * from new_player_monthly_07 order by
其中get_player_src.php:
1. $fr=fopen("php://stdin","r");
2. $curr_qid
3. $curr_src
4. $curr_logintime=null;
5. while(!feof($fr))
6. {
7. $input = fgets($fr,1024);
8. $input = rtrim($input);
9. $arr = explode("\t", $input);
10. $qid = trim($arr[0]);
11. if(emptyempty($curr_qid)||$curr_qid != $qid)
12. {
13. $curr_qid = $qid;
14. echo $input."\n";
15. }
16. }
17. fclose ($fr);
平台级新用户数:
1. select count(*) from
平台级各渠道新用户汇总:
1. create table new_player_src_stat_07 as select src,count(*) from new_player_monthly_07 group by