Python编程语言是一种广泛应用于各个领域的高级编程语言,它的简洁和易读性使得许多人选择使用Python进行编程。在Python中,有许多有趣的编程项目,其中贪吃蛇游戏是一个非常经典的项目。贪吃蛇游戏不仅可以帮助初学者熟悉Python语法和编程逻辑,还可以提高编程技能和逻辑思维能力。
在贪吃蛇游戏中,玩家通过控制一条蛇在屏幕上移动,吃掉食物并避免撞到墙壁或自己的身体。游戏的难度随着吃到的食物数量增加而增加,挑战玩家的反应速度和操作技巧。
下面是一个简单的Python贪吃蛇游戏示例代码:
import pygame
import random
pygame.init()
width = 800
height = 600
screen = pygame.display.set_mode((width, height))
pygame.display.set_caption('Snake Game')
snake_pos = [100, 50]
snake_body = [[100, 50], [90, 50], [80, 50]]
food_pos = [random.randrange(1, width//10) * 10, random.randrange(1, height//10) * 10]
food_spawn = True
direction = 'RIGHT'
change_to = direction
score = 0
clock = pygame.time.Clock()
def game_over():
font = pygame.font.SysFont('Arial', 30)
text = font.render('Your score is: ' + str(score), True, (255, 255, 255))
screen.blit(text, [width//2 - 100, height//2])
pygame.display.flip()
pygame.time.wait(2000)
pygame.quit()
def show_score(choice=1):
font = pygame.font.SysFont('Arial', 30)
text = font.render('Score: ' + str(score), True, (255, 255, 255))
screen.blit(text, [0, 0])
def draw_snake(snake_body):
for pos in snake_body:
pygame.draw.rect(screen, (0, 255, 0), pygame.Rect(pos[0], pos[1], 10, 10))
def draw_food(food_pos):
pygame.draw.rect(screen, (255, 0, 0), pygame.Rect(food_pos[0], food_pos[1], 10, 10))
while True:
for event in pygame.event.get():
if event.type == pygame.QUIT:
pygame.quit()
keys = pygame.key.get_pressed()
for key in keys:
if keys[pygame.K_UP]:
change_to = 'UP'
if keys[pygame.K_DOWN]:
change_to = 'DOWN'
if keys[pygame.K_LEFT]:
change_to = 'LEFT'
if keys[pygame.K_RIGHT]:
change_to = 'RIGHT'
if change_to == 'UP' and direction != 'DOWN':
direction = 'UP'
if change_to == 'DOWN' and direction != 'UP':
direction = 'DOWN'
if change_to == 'LEFT' and direction != 'RIGHT':
direction = 'LEFT'
if change_to == 'RIGHT' and direction != 'LEFT':
direction = 'RIGHT'
if direction == 'UP':
snake_pos[1] -= 10
if direction == 'DOWN':
snake_pos[1] += 10
if direction == 'LEFT':
snake_pos[0] -= 10
if direction == 'RIGHT':
snake_pos[0] += 10
snake_body.insert(0, list(snake_pos))
if snake_pos[0] == food_pos[0] and snake_pos[1] == food_pos[1]:
score += 1
food_spawn = False
else:
snake_body.pop()
if not food_spawn:
food_pos = [random.randrange(1, width//10) * 10, random.randrange(1, height//10) * 10]
food_spawn = True
screen.fill((0, 0, 0))
draw_snake(snake_body)
draw_food(food_pos)
show_score()
if snake_pos[0] < 0 or snake_pos[0] > width-10:
game_over()
if snake_pos[1] < 0 or snake_pos[1] > height-10:
game_over()
for block in snake_body[1:]:
if snake_pos[0] == block[0] and snake_pos[1] == block[1]:
game_over()
pygame.display.update()
clock.tick(15)
通过以上代码,我们可以创建一个简单