欧拉定理 就是a和m互质，且a小于m，设x为欧拉函数的值，则a^x%m=1恒成
n素数的定义： n 不能够被[2，sqrt(n)?]中任意一个整数整除，则n是素数。 n
哥德巴赫猜想的问题描述 任何偶数哥德巴赫猜想:n大于等于4,存在至少一对素
抱歉Problem Description 非常抱歉，本来兴冲冲地搞一场练习赛，由于我准备不足
double err = 1e-6; if(fabs((int)s-s)<err) printf("%.lf\n",s); else printf("%.2lf\n",s);
9余数定理可以验证灯饰两边是否相等
# include <iostream># include <cstdio># include <algorithm>using namespace std;int main(){ int n,a[10009]; int i,t; while(scanf("%d",&n),n!=0){ int t = 1;
Reverse NumberProblem Description Welcome to 2006’4 computer college programming contest!Specially, I give my best regards to all freshmen! You are the future of HDU ACM! And now, I must tell you tha
Basically Speakinghttp://acm.hdu.edu.cn/showproblem.php?pid=1335Problem Description The Really Neato Calculator Company, Inc. has recently hired your team to help design their Super Neato Model I
A Simple TaskProblem Description Given a positive integer n and the odd integer o and the nonnegative integer p such that n = o2^p.ExampleFor n = 24, o = 3 and p = 3.TaskWrite a program which for eac
利用矢量叉积判断是逆时针还是顺时针。 设A(x1,y1),B(x2,y2),C(x3,y3),则三角形两边的矢量分别是： AB=(x2-x1,y2-y1), AC=(x3-x1,y3-y1) 则AB和AC的叉积为：(2*2的行列式) |x2-x1, y2-y1| |x3-x1, y3-y1| 值为：(x2-x1)*(y3-y1) - (y2-y1)*(x3-x1
二者都是从终端读入字符串。功能为1、 gets功能为读入一行，并将换行符转换为字符串结束符。2、 scanf("%s",s);读入时，遇到空白字符，包括空格，制表符，换行符时均会停止输入。从功能上可以看出不同之处：1 终止条件不同。gets只有遇到\n时才会结束输入，而scanf遇到空格或制表符时，也会结束输入。比如输入"test string\n"。用gets得到的字符串为"test strin
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