LeetCode题解(0157)：用Read4读取N个字符Python)

题目：原题链接（简单）

标签：字符串

解法	时间复杂度	空间复杂度	执行用时
Ans 1 (Python)	O ( N ) O(N) O(N)	O ( 1 ) O(1) O(1)	36ms (84.89%)
Ans 2 (Python)
Ans 3 (Python)

解法一：

class Solution:
    def read(self, buf, n):
        now, remain = 0, n
        while True:
            cache = [" "] * 4
            size = read4(cache)
            for i in range(min(remain, size)):
                buf[now] = cache[i]
                now += 1
            remain -= size
            if size < 4 or remain <= 0:
                return now