题目:原题链接(中等)

标签:数组、动态规划

解法 时间复杂度 空间复杂度 执行用时
Ans 1 (Python) O ( N × M ) O(N×M) O(N×M) O ( N × M ) O(N×M) O(N×M) 88ms (6.12%)
Ans 2 (Python)
Ans 3 (Python)

解法一:

class Solution:
    _BIG = 200 * 100

    def minPathSum(self, grid: List[List[int]]) -> int:
        m, n = len(grid), len(grid[0])

        dp = [[0] * n for _ in range(m)]

        for i in range(m):
            for j in range(n):
                if i == 0 and j == 0:
                    dp[i][j] = grid[i][j]
                else:
                    dp[i][j] = grid[i][j] + min((dp[i - 1][j] if i > 0 else self._BIG),
                                                (dp[i][j - 1] if j > 0 else self._BIG))

        return dp[-1][-1]