【洛谷P2927 [USACO08DEC]拼图游戏Jigsaw Puzzles】深搜_ios

 

【洛谷P2927 [USACO08DEC]拼图游戏Jigsaw Puzzles】深搜_i++_02

 

其实,随便搜了一搜就可以AC了!!!

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亏我纠结了这么久= =

【洛谷P2927 [USACO08DEC]拼图游戏Jigsaw Puzzles】深搜_#include_03【洛谷P2927 [USACO08DEC]拼图游戏Jigsaw Puzzles】深搜_ios_04
 1 #include<cstdio>
 2 #include<cstdlib>
 3 #include<cstring>
 4 #include<iostream>
 5 #include<algorithm>
 6 #include<queue>
 7 #include<cmath>
 8 using namespace std;
 9 #define Maxn 110
10 
11 struct node
12 {
13     int num,ax[5];
14 }t[Maxn];
15 
16 bool cmp(node x,node y) {return x.num<y.num;} 
17 
18 int r,c;
19 char s[0];
20 
21 int w[10][10],b[10][10];
22 bool vis[Maxn];
23 
24 void output()
25 {
26     for(int i=1;i<=r;i++)
27      for(int j=1;j<=c;j++)
28      {
29          printf("%d ",t[b[i][j]].num);
30          for(int k=0;k<4;k++)
31          {
32              int x=t[b[i][j]].ax[(k+w[i][j])%4];
33              if(x==0) printf("0 ");
34              else printf("%c ",x+'a'-1);
35          }
36          printf("\n");
37      }
38 }
39 
40 bool ok=0;
41 
42 void ffind(int x,int y)
43 {
44     if(x==r+1)
45     {
46         output();
47         ok=1;
48         return;
49     }
50     if(y==c+1) {ffind(x+1,1);return;}
51     for(int i=1;i<=r*c;i++) if(!vis[i])
52     {
53         for(int k=0;k<4;k++) 
54           if(t[i].ax[k]==t[b[x-1][y]].ax[(w[x-1][y]+2)%4] && t[i].ax[(k+3)%4]==t[b[x][y-1]].ax[(w[x][y-1]+1)%4])
55         {
56             if(y==c&&t[i].ax[(k+1)%4]!=0) continue;
57             if(y!=c&&t[i].ax[(k+1)%4]==0) continue;
58             if(x!=r&&t[i].ax[(k+2)%4]==0) continue;
59             if(x==r&&t[i].ax[(k+2)%4]!=0) continue;
60             w[x][y]=k;
61             b[x][y]=i;
62             vis[i]=1;
63             ffind(x,y+1);
64             vis[i]=0;
65             if(ok==1) return;
66         }
67     }
68 }
69 
70 int main()
71 {
72     scanf("%d%d",&r,&c);
73     for(int i=1;i<=r*c;i++)
74      {
75          scanf("%d",&t[i].num);
76          for(int k=0;k<4;k++)
77          {
78              scanf("%s",s);
79              if(s[0]=='0') t[i].ax[k]=0;
80              else t[i].ax[k]=s[0]-'a'+1;
81          }
82      }
83     memset(vis,0,sizeof(vis));
84     for(int i=0;i<4;i++) t[0].ax[i]=0;
85     memset(b,0,sizeof(b));
86     memset(w,0,sizeof(w));
87     sort(t+1,t+1+r*c,cmp);
88     ffind(1,1);
89     return 0;
90 }
View Code

 

2016-11-14 21:56:40