Given a positive integer, return its corresponding column title as appear in an Excel sheet.
For example:
1 -> A 2 -> B 3 -> C ... 26 -> Z 27 -> AA 28 -> AB
思路:
相当于10进制转26进制。与一般不一样的是10进制对应的是0 - 9。而这个26进制对应的是 A(1)- Z(26), 没有0。
我的代码:
string convertToTitle(int n) { string ans; while(n != 0) { int num = n % 26; n /= 26; if(num != 0) { ans.push_back(num - 1 + 'A'); } else { ans.push_back('Z'); n--; } } reverse(ans.begin(), ans.end()); return ans; }
大神精简的代码:
string convertToTitle(int n) { string res; char tmp; while(n){ n -= 1; //这里相当于把A-Z表示成了0-25就与一般的表达一样了 tmp = 'A' + n % 26; res = tmp + res; n /= 26; } return res; }
Given a column title as appear in an Excel sheet, return its corresponding column number.
For example:
A -> 1 B -> 2 C -> 3 ... Z -> 26 AA -> 27 AB -> 28
思路:26进制转10进制。 以AAA为例 AAA = A * 262 + A * 261 + A * 260;
int titleToNumber(string s) { int ans = 0; int factor = 1; while(!s.empty()) { ans = ans + (s.back() - 'A' + 1) * factor; s.pop_back(); factor *= 26; } return ans; }
大神精简版的:
int result = 0; for (int i = 0; i < s.size(); result = result * 26 + (s.at(i) - 'A' + 1), i++); return result;