喝汽水，1瓶汽水1元，2个空瓶可以换一瓶汽水，给20元，可以多少汽水

第一种方法 #include<stdio.h> #include<Windows.h> #pragma warning(disable:4996) int Qishui(int n) { int total = 0; total += n; for (; n >= 2;n=n/2+n%2) { total += n / 2; } return total; } int main() { int money = 0; printf("你有多少钱："); scanf_s("%d", &money); int ret = Qishui(money); printf("可以买%d瓶汽水\n", ret); system("pause"); return 0; }

第二种方法 #include<stdio.h> #include<Windows.h> #pragma warning(disable:4996) int Qishui(int money) { int total = money; int empty = money; while (empty > 1) { total += empty / 2; empty = empty / 2 + empty % 2; } return total; } int main() { int money = 0; printf("你有多少钱："); scanf_s("%d", &money); int ret = Qishui(money); printf("可以买%d瓶汽水\n", ret); system("pause"); return 0; }