Write a program which performs the following operations to a binary search tree T T T by adding the find operation to A: Binary Search Tree I.
insert
k
k
k: Insert a node containing
k
k
k as key into
T
T
T.
find
k
k
k: Report whether
T
T
T has a node containing
k
k
k.
print: Print the keys of the binary search tree by inorder tree walk and preorder tree walk respectively.
Input
In the first line, the number of operations m m m is given. In the following m m m lines, operations represented by insert k k k, find k k k or print are given.
Output
For each find k k k operation, print “yes” if T T T has a node containing k k k, “no” if not.
In addition, for each print operation, print a list of keys obtained by inorder tree walk and preorder tree walk in a line respectively. Put a space character before each key.
Constraints
The number of operations
≤
500
,
000
\leq 500,000
≤500,000
The number of print operations
≤
10
\leq 10
≤10.
−
2
,
000
,
000
,
000
≤
k
e
y
≤
2
,
000
,
000
,
000
-2,000,000,000 \leq key \leq 2,000,000,000
−2,000,000,000≤key≤2,000,000,000
The height of the binary tree does not exceed 100 if you employ the above pseudo code.
The keys in the binary search tree are all different.
Sample Input 1
10
insert 30
insert 88
insert 12
insert 1
insert 20
find 12
insert 17
insert 25
find 16
print
Sample Output 1
yes
no
1 12 17 20 25 30 88
30 12 1 20 17 25 88
Reference
Introduction to Algorithms, Thomas H. Cormen, Charles E. Leiserson, Ronald L. Rivest, and Clifford Stein. The MIT Press.
Code
/*
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10 00 11 ^^^^^ 1 0 1.
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1 .. .1 ^.^ ^^^ 1 ^ ^0001
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0 ^. 0 ^0 1 ^^^ 0.
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1.1 00 00 10^
..^ 1. ^. 1.
0 1 ^. 00 00 .^
^ ^. ^ 1 00 ^0000^ ^ 01
1 0 ^. 00.0^ ^00000 1.00.1 11
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1 1 0.
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1 1
^ ^ .0
1 ^ 1
.. 1.1 ^0.0
^ 0 1..01^^100000..0^
1 1 ^ 1 ^^1111^ ^^
0 ^ ^ 1 1000^
.1 ^.^ . 00
.. 1.1 0. 0
1. . 1. .^
1. 1 1. ^0
^ . ^.1 00 01
^.0 001. .^
*/
// Virtual_Judge —— Binary Search Tree I Aizu - ALDS1_8_A.cpp created by VB_KoKing on 2019-05-09:18.
/* Procedural objectives：
Variables required by the program:
Procedural thinking：
Functions required by the program:
Determination algorithm:
Determining data structure:
*/
/* My dear Max said：
"I like you,
So the first bunch of sunshine I saw in the morning is you,
The first gentle breeze that passed through my ear is you,
The first star I see is also you.
The world I see is all your shadow."
FIGHTING FOR OUR FUTURE！！！
*/
#include <iostream>
#include <cstdlib>
using namespace std;
struct Node {
int key;
Node *right, *left, *parent;
};
Node *root, *NIL;
Node *find(Node *u,int k)
{
while (u!=NIL&&k!=u->key)
{
if (k<u->key) u=u->left;
else u=u->right;
}
return u;
}
void insert(int k) {
Node *y = NIL;
Node *x = root;
Node *z;
z = (Node *) malloc(sizeof(Node));
z->key = k;
z->left = NIL;
z->right = NIL;
while (x != NIL) {
y = x;
if (z->key < x->key)
x = x->left;
else
x = x->right;
}
z->parent = y;
if (y == NIL)
root = z;
else {
if (z->key < y->key)
y->left = z;
else y->right = z;
}
}
//前序遍历
void pre_parse(Node *u) {
if (u == NIL) return;
cout << " " << u->key;
pre_parse(u->left);
pre_parse(u->right);
}
//中序遍历
void in_parse(Node *u) {
if (u == NIL) return;
in_parse(u->left);
cout << " " << u->key;
in_parse(u->right);
}
int main() {
int n;
string com;
cin >> n;
for (int i = 0; i < n; i++) {
cin >> com;
if (com == "insert") {
int x;
cin >> x;
insert(x);
} else if (com == "print") {
in_parse(root);
cout << endl;
pre_parse(root);
cout << endl;
} else if (com=="find"){
int x;
cin>>x;
Node *t=find(root,x);
if (t!=NIL) cout<<"yes"<<endl;
else cout<<"no"<<endl;
}
}
return 0;
}
