这次只有一道题:数制转换,采用了顺序栈和链栈。这是栈的一个很经典的应用,不过结构定义和算法实现方法不唯一,如果大家有其他的算法实现,在下面评论哦!

目录

​习题一:数制转换​

​1、题目​

​2、顺序栈实现​

​代码​

​执行结果​

​3、链栈实现​

​代码​

​执行结果​


习题一:数制转换

1、题目

将一个十进制的数转化为八进制。

2、顺序栈实现

代码

#define MAXSTACKSIZE 20
#define STACKCREMENT 5
#include<iostream>
#include<malloc.h>

using namespace std;

typedef struct {
int *base;
int *top;
int stacksize;
}SqStack;

int InitStack(SqStack &S) {
S.base = (int*)malloc(MAXSTACKSIZE * sizeof(SqStack));
if (!S.base)
{
exit(OVERFLOW);
}
S.top = S.base;
S.stacksize = MAXSTACKSIZE;
return 1;
}

int Push(SqStack &S, int e) {
if (S.top - S.base == S.stacksize) {
S.base = (int *)realloc(S.base, (S.stacksize + STACKCREMENT) * sizeof(SqStack));
if (!S.base)
{
cout << "空间分配失败" << endl;
exit(OVERFLOW);
}
S.stacksize += STACKCREMENT;
}
*S.top++ = e;
return 1;
}

int Pop(SqStack &S, int &e) {
if (S.top == S.base)
return 0;
e = *--S.top;
return 1;
}

int DecimalismToOctal(SqStack &S, int decimalism, int &octal) {
int remainder;
int r;
octal = 0;
do{
remainder = decimalism % 8;
Push(S, remainder);
decimalism /= 8;
} while (decimalism);

while (S.top != S.base)
{
octal *= 10;
Pop(S, r);
octal += r;

}
return 1;
}

void main() {
SqStack S;
InitStack(S);
int decimalism_a = 160;
int octal_a;
DecimalismToOctal(S, decimalism_a, octal_a);

cout << "将十进制" << decimalism_a << "转化为八进制后的值为" << octal_a << endl;

}

执行结果

【数据结构周周练】004顺序栈与链栈 -数制转换_ooc

3、链栈实现

代码

#include<iostream>
#include<malloc.h>

using namespace std;

typedef struct LNode {
int data;
struct LNode *next;
}LNode, *LinkStack;

int InitStack(LinkStack &LS) {
LS = (LinkStack)malloc(sizeof(LNode));
if (!LS)
{
cout << "空间分配失败" << endl;
return OVERFLOW;
}
LS->next = NULL;
return 1;
}

int Push(LinkStack &LS, int e) {
LS->data = e;
LinkStack p = (LinkStack)malloc(sizeof(LNode));
p->next = LS;
LS = p;
return 1;
}

int Pop(LinkStack &LS, int &e) {
if (LS->next)
{
LinkStack p = LS->next;
e = p->data;
LS->next = p->next;
free(p);
return 1;
}
return 0;
}

int DecimalismToOctal(LinkStack &LS, int decimalism, int &octal) {
int r;
octal = 0;
while (decimalism)
{
r = decimalism % 8;
decimalism /= 8;
Push(LS, r);
}
while (LS->next)
{
octal *= 10;
Pop(LS, r);
octal += r;

}
return 1;
}
void main() {
LinkStack S;
InitStack(S);
int decimalism_a = 120;
int octal_a;
DecimalismToOctal(S, decimalism_a, octal_a);

cout << "将十进制" << decimalism_a << "转化为八进制后的值为" << octal_a << endl;
}

执行结果

【数据结构周周练】004顺序栈与链栈 -数制转换_顺序栈_02