gubojun的博客_ACM-hdoj

北大ACM poj3982

//3982//大数相加 #include#includeint sum[101][100];//存储计算结果 char a1[100],b1[100],c1[100];void tran(char a[],int k)//把输入的字符串转化为整型数组 { int l=strlen(a); int i=0,j; for(j=l-1;j>=0;j--) {

c

C

存储

i++

字符串

原创 2023-08-21 16:46:10 51 阅读

北大ACM poj2350 Above Average

Above AverageDescriptionIt is said that 90% of frosh expect to be above average in their class. You are to provide a reality check.InputThe first line of standard input contains an integer C

integer

float

output

each

input

原创 2023-08-21 16:44:29 69 阅读

北大ACM poj1068 Parencodings

题目大意：求一对（）中的括号的对数/*(((()()())))000010101111 4 5 6666 r 当前')'前的'('的总数 1 1 1456 answer 3 4 5210 r2 与当前')'对应的'('的序号 (((()(())))(()()))000010011110010

Parencodings 北大ACM p

入栈

数据

i++

原创 2023-08-21 16:44:04 67 阅读

北大ACM poj1125 Stockbroker Grapevine(Floyd算法)

/*首先，题目可能有多组测试数据，每个测试数据的第一行为经纪人数量N（当N=0时，输入数据结束），然后接下点到第a号结点的孤长为b）

i++

数据

结点

原创 2023-08-21 16:43:21 63 阅读

杭电ACM-HDOJ1466计算直线的交点数(动态规划)

/** * problem:杭电OJ1466动态规划-计算直线的交点数

i++

#include

ios

原创 2023-08-21 16:41:54 50 阅读

杭电ACM HDU 2616 Kill the monster

/*暴力搜索*/#include int c;//统计需要的spell的数量int n;//spell的种类数int m;//怪兽的血量int spell[11][2];void search(int b,int f[],int count,int m){ if(b0){ for(int i=0;i<n;i++){ if

HDU

ACM

i++

#include

初始化

原创 2023-08-21 16:41:42 46 阅读

杭电ACM HDOJ 1174 爆头

#include #include double x1=a.x; double y1=a.y; double z1=a.z;

hdoj

HDOJ

杭电ACM

#include

ios

原创 2023-08-21 16:41:35 48 阅读

杭电ACM HDOJ 2143 box

#include #include

hdoj

HDOJ

杭电ACM

#include

i++

原创 2023-08-21 16:41:31 51 阅读

杭电ACM HDOJ 1265

/** * problem:杭电OJ1465(错排公式) * time:2013-2-6

#include

ios

错排公式

原创 2023-08-21 16:41:28 46 阅读

杭电ACM HDU 2143 box

#include #include using namespace std; __int64 a,b,c; int isluck(){ int i,j; __int64 t; for(i=0;i<3;i++){ if(a+b==c)return 1; if(a*b==c)return 1; if(a!=0&&b!=0&&(a%b==c || b%a==c))return 1;

#include

i++

ios

原创 2023-08-21 16:41:24 61 阅读

杭电ACM HDU 1004

#include #include #include int cmp (void const *a,void const *b){ return strcmp((char *)a,(char *)b); } int main(){ int n; char color[1000][16]; while(scanf("%d",&n)&&n){ fo

#include

i++

原创 2023-08-21 16:41:18 57 阅读

杭电ACM HDU 1002

#include #include

#include

原创 2023-08-21 16:41:01 37 阅读

杭电ACM HDU 1013

#include char str[1001]; int main(){ while(scanf("%s",str)&&(str[0]-'0')){ int i=0; int sum=0; while(str[i]){ sum+=str[i++]-'0'; } int n=sum;

i++

#include

原创 2023-08-21 16:40:53 49 阅读

杭电ACM HDU 1008

#include int main(){ int n; int pre,f; int sum; while(scanf("%d",&n)&&n){ sum=n*5; pre=0; for(int i=0;i<n;i++){ scanf("%d",&f); if(f>pr

i++

#include

原创 2023-08-21 16:40:50 65 阅读

杭电ACM HDU 1019 Least Common Multiple

Least Common Multiple Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)

hdu

HDU

Hdu

杭电ACM

Java

原创 2023-08-21 16:40:46 49 阅读

杭电ACM HDU 1032 The 3n + 1 problem

The 3n + 1 problem Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 15209 Accepted Submission(s): 5602 Problem Description Problems i

hdu

HDU

Hdu

杭电ACM

Java

原创 2023-08-21 16:40:13 65 阅读

航电ACM HDU 1228 A + B

A + B Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)

ACM

acm

hdu

HDU

Hdu

原创 2023-08-21 16:40:07 78 阅读

杭电ACM HDU 2548 两军交锋

两军交锋Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 3030 Accepted Submission(s): 2068Proble

ACM

Java

Memory

程序设计竞赛

原创 2023-08-21 16:40:03 16 阅读

杭电ACM HDU 2689 Sort it

#include int c;void bubble_sort(int a[],int n){ int i,j,t,flag; for(i=n-1,flag=1;i>=1&&flag;i--){ flag=0;//是否进行过排序的标记变量 for(j=0;j<i;j++){ if(a[j]>a[j+1]){

c++

i++

标记变量

原创 2023-08-21 16:39:23 70 阅读

杭电ACM HDU 3283 The Next Permutation

The Next PermutationTime Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 618 Accepted Submission(s): 439Problem DescriptionFor this

git

#include

Java

原创 2023-08-21 16:39:18 32 阅读

杭电ACM HDU 2674 N！Again

N！AgainTime Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 2395 Accepted Submission(s): 1338Problem DescriptionWhereIsHeroFrom:

HDU

ACM

杭电

2674

Java

原创 2023-08-21 16:39:13 45 阅读

杭电ACM HDU 3424 Range

RangeTime Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 245 Accepted Submission(s): 153Problem DescriptionSome automobiles display

acm

HDU

3424

sed

Java

原创 2023-08-21 16:38:33 60 阅读

杭电ACM HDU 2502 月之数

月之数Time Limit: 1000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 4860 Accepted Submission(s): 2862Problem Description当寒月还在读大一的时候，他在一本武林秘籍中（据后

ACM

二进制数

Java

Memory

原创 2023-08-21 16:38:23 62 阅读

杭电ACM HDU 4156 Egypt

EgyptTime Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 599 Accepted Submission(s): 427Problem DescriptionA long time ago, the Egy

ACM

Java

ide

Memory

原创 2023-08-21 16:38:17 32 阅读

杭电ACM HDU 2576 Another Sum Problem

Another Sum ProblemTime Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 1086 Accepted Submission(s): 286Problem DescriptionFunnyAC l

ACM

Java

Problem

Memory

原创 2023-08-21 16:38:01 45 阅读

杭电ACM HDU 2524 矩形A+B

矩形A + BTime Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 3159 Accepted Submission(s): 2374Problem Description给你一个高为n ，宽为m列的网格，计算出

ACM

Java

Memory

Programming

原创 2023-08-21 16:37:56 45 阅读

杭电ACM HDU 2203 亲和串

亲和串Time Limit: 3000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 5641 Accepted Submission(s): 2546Problem Description人随着岁数的增长是越大越聪明还是越大越笨，这是一

ACM

KMP

搜索

C

字符串

原创 2023-08-21 16:37:34 71 阅读

杭电ACM HDU 3790 最短路径问题

最短路径问题Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 7754 Accepted Submission(s): 2314Problem Description给你n个点，m条无向边，每条边都有长度d和

初始化

i++

最短距离

原创 2023-08-21 16:37:23 33 阅读

杭电ACM HDU 3139 Soda Surpler

Soda SurplerTime Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 234 Accepted Submission(s): 171Problem DescriptionTim is an a

Java

Memory

#include

原创 2023-08-21 16:37:13 53 阅读

杭电ACM HDU 1038 Biker's Trip Odometer

Biker's Trip OdometerTime Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 2810 Accepted Submission(s): 1922Problem DescriptionMost b

#define

Java

Memory

原创 2023-08-21 16:36:55 46 阅读

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