Cosine similarity is a measure of similarity between two vectors of an inner product space that measures the cosine of the angle between them. The cos
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2016-07-01 03:11:00
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1.similar_gen.cpp#include <string.h>#include <iostream>#include <string>#include <algorithm>#include "boost/noncopyable.hpp"using namespace std;class similar_gen : public boost
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2022-12-01 17:00:34
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Given two sets of integers, the similarity of the sets is defined to be /, where Nc is the number of distinct common numbers shared by the two sets
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2020-05-05 11:31:00
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https://www.cs.utah.edu/~jeffp/teaching/cs5955/L4-Jaccard+Shingle.pdf https://www.cs.utah.edu/~jeffp/teaching/cs5955/L5-Minhash.pdf 【可测空间 convert the
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2017-10-09 14:23:00
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题目描述Given two sets of integers, the similarity of t
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2023-03-02 09:17:15
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1、similarity函数接收两个列表,并返回由两个列表中相同元素组成的列表。2、函数使用列表推导,遍历所有a列表中的元素,并使用in关键词来判断这些元素是否存在于b列表中。实例def similarity(a, b): return [item for item in a if item in b] # EXAMPLESsimilarity([1, 2, 3], [1, 2, 4]) # [
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2023-02-09 10:34:59
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HDU_3718
我们首先要把字符串中的字符转化成意义相同的[0,k-1]之间的数,然后顺序扫描一遍数组,就可以得到两组数之间的各种匹配的最大值,这样就完成了建图。
之后运用KM算法求最优匹配即可。
#include<stdio.h>#include<string.h>#define MAXD 30#define MAXN 10010#define INF 1000000
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2011-10-05 15:29:00
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题目题意:给定两个集合,求 差/并 的结果#include<iostream>#incn>...
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2023-06-27 10:16:59
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Given two sentences words1, words2 (each represented as an array of strings), a
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2022-08-03 21:41:40
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Given two sets of integers, the similarity of the sets is defined to be Nc/Nt*100%, where Nc is the number of distinct common numbers shartal number of distinct n
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2023-09-05 09:31:16
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传送门boynextdoor每颗子树设有xxx个深度为dxd_xdx,yyy个深度为dyd_ydy…那么可以哈希成x∗basedx+y∗base
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2022-02-08 13:45:31
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1063 Se
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2022-09-15 10:53:58
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Given two sets of integers, the similarity of the sets is defined to be Nc/Nt*100%, where Nc is the number of distinct common numbers shared by the tw
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2018-04-23 11:03:00
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传送门密码boynextdoor每颗子树设有xxx个深度为dxd_xdx,yyy个深度为dyd_ydy…那么可以哈希成x∗basedx+y∗basedy...x*base^{d_x}+y*base^{d_y}...x∗basedx+y∗basedy...判断一下就好了把basebasebase适当放大可以减小冲突率#include <bits/stdc++.h>using namespace std;#define int long long#define ULL un
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2021-08-27 09:59:04
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题意: 给你一棵树,问你有多少个组合的相似; 相似是a结点的子树和b结点的子树的每一层的结点数相等; 思路: HASH来搞; 主要也没学过散列表,以及一个散列函数的构造; 其实看下面程序很简单,手跑案例就可以发现,每个结点有:a*pri^b,系数a就是在该节点下的b层结点个数。 暂时只理解到这个...
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2016-10-05 00:53:00
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1. 题目 Given two sets of integers, the similarity of the sets is defined to be Nc/Nt×100%, where Nc is the number of distinct common numbers shared by ...
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2021-10-29 12:46:00
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由于二分图匹配的时候两边的点数不相同,所以要把两边
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2023-07-05 20:13:46
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原代码,在$\color$上能取得$25pts$的满分好成绩,但在其他地方都超时了,gg。 set<int> S[55]; double res[55][55]; int n,m; void init() { for(int i=1;i<=n;i++) for(int j=i+1;j<=n;j++)
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2021-02-17 12:07:00
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Given two sets of integers, the similarity of the sets is defined to be Nc/Nt*100%, where Nc is the number of distinct common numbers shared by the tw
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2018-01-02 21:47:00
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题目传送门 - HDU3718 题意概括 直接描述输入吧 首先一个T(T<15),表示数据组数。 每组数据,首先三个数:len,k,m,分别表示接下来要读入的字符串的长度、每一个字符串中出现
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2018-01-14 22:56:00
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