Puzzled ElenaTime Limit: 2500msMemory Limit: 131072KBThis problem will be judged onHDU. Original ID:546864-bit integer IO format:%I64d Java class name...
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2015-10-24 11:08:00
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考虑对一个集合求莫比乌斯反演的过程，最终答案即$\sum\limits_{d|ai}\mu(d)\cdot calc(d)$（calc(d)表示i子树中d倍数的个数）dfs时维护当前遍历到的点中i倍数的个数，对i搜之前和i搜完后差分一下就可以得到i子树的信息，用上述式子计算即可 1 #include
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2019-10-15 13:06:00
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dfs遍历树+莫比乌斯反演..
#include
int not_prime[
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2023-07-05 20:01:42
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一颗树每个点上有点权，求每个点与它子树中的点的点权是否互质。cnt(d)表示i的倍数出现次数，则答案=∑d|viμ(d)cnt(d)dfs 的时候后减前即可。由于2∗3∗5∗7∗11∗13>105 ， 所以一个数的质因子数不超过6个 复杂度可以保证#include<cstdio>#include<cstring>#include<algorithm>#i
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2015-10-01 22:58:34
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题意: 给出一棵树,每个点上有权值.然后求每棵子树中与根节点互质( $gcd(a, b) = 1$ )的节点个数. 分析: 对于一颗子树来说,设根节点的权值为$u$, $count_i$表示权值为$i$的倍数的节点的个数. 那么根据莫比乌斯反演,与$u$互质的节点的个数为$\sum_{d...
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2015-10-07 11:43:00
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题意：给定一棵带权树，求每个点与其子树结点的权值互质的个数。 析：首先先要进行 dfs 遍历，len[i] 表示能够整除 i 的个数，在遍历的前和遍历后的差值就是子树的len值，有了这个值，就可以使用莫比斯反演了。注意如果子树的权值是1，还要加上它本身。 代码如下：
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2018-02-03 14:17:00
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题干：
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2022-06-15 11:07:44
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Problem Description
XXX is puzzled with the quest...
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2023-02-07 12:11:52
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I - Transformation Yuanfang is puzzled with the question below: There are n integers, a 1, a 2, …, a n. The initial values of them are 0. There are fo
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2019-05-12 20:35:00
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ip dhcp excluded-address 192.168.1.0 192.168.1.50 排除dhcp分配的ip地址
ip domain-name puzzled 此命令是为路由器设置一个域名，也可以认为这个路由器是属于哪个域
ip dhcp pool puzzled 定义dhcp地
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2012-08-24 21:54:23
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Inversion of ControlWhen these containers talk about how they are so useful because they implement "Inversion of Control" I end up very puzzled. Inversion of control is a common characteristic of fra
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2011-10-31 00:55:00
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Yuanfang is puzzled with the question below: There are n integers, a 1, a 2, …, a n. The initial values of them are 0. There are four kinds of operati
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2017-09-17 15:53:00
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IntroductionModeless dialog boxes have often puzzled newbie programmers. Basically a modeless dialog box is one that allows us to interact with other windows even when the modeless dialog is still
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2022-12-23 07:46:28
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Puzzled Elena Time Limit: 5000/2500 MS (Java/Others) Memory Limit: 131072/131072 K (Java/Others)Total Submission(s): 1247 Accepted Submission(s): 370
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2021-07-21 15:50:45
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魔术包唤醒 When you are tweaking or adjusting various settings on your computer, sooner or later you will likely run across some options that leave you puzzled or confused. With that in mind, to
Problem Description
Coco is a clever boy, who is good at mathematics. However, he is puzzled by a difficult mathematics problem. The problem is: Given three integers N, K and M, N may adds (‘+’) M
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2022-11-09 18:27:59
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Problem Description XXX is puzzled with the question below: 1, 2, 3, ..., n (1<=n<=400000) are placed in a line. There are m (1<=m<=1000) operations o
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2016-02-23 21:15:00
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Now, there are so many articles to introduce how to create animation in XAML by Blend, so I don’t plan to say more on this topic. It make many people puzzled “Silverlight is just Microsoft... Read More
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2010-02-24 17:02:00
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Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 3639 Accepted Submission(s): 1047Problem Description XXX is puzzled with the question below
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2021-07-06 14:34:49
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一、内容 Yuanfang is puzzled with the question below:There are n integers, a 1, a 2, …, a n. The initial values of them are 0. There are four kinds of operations.Operation 1: Add c to each number betwe...
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2021-08-27 14:18:06
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