yesterday, I got two bad news that two negotiated project were suspended by the customers, surely, I felt very blue so that I could not sleep until further late
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2009-10-13 09:04:38
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We Need Dreams We all want to believe that we are capable of great feats of reaching our fullest potential. We need dreams. They give us a virsion of a butter future. They nouri
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2015-11-22 23:26:16
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##Today's topic ###TALKING ABOUT CHILDHOOD DREAMS For most people, dreams and reality are very far apart. Talk about the dreams you had as a child, an ...
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2021-05-12 00:20:00
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Java has been a programmer’s dream and what’s the better way to quantify Java’s popularity with the new version release Java 13. After the initial Java enhancement proposal, there have been adva
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2023-07-19 21:11:34
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我曾经很长一段时间着迷于CS、WOW，偶尔看看摔角，很多视频里都有这首歌
《Boulevard of Broken Dreams》-Green Day
I walk a lonely road 我走在寂
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2007-01-17 16:31:21
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I walk a l roadThe that I have ever knownD know where it goesBut it's home to me and I walk aloneI walk this empty streetOn the Boulevard of Broken DreamsWhere the city sleepsand I'm the and I wal
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2006-10-15 22:58:40
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题目 题目链接：https://codeforces.com/contest/1586/problem/F 一张 \(n\) 个点的竞赛图，所有边都是从编号小的点连向编号大的点。 如果需要给每条边染上色，求最少需要多少种颜色，使得存在一种染色方法，不存在长度为 \(k\) 的路径都是同一种颜色。 \ ...
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2021-10-18 08:57:00
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The National Basketball Association's Basketball Without Borders Africa program this year brought NBA players and coaches to Senegal where they trained some of the best young players on
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2010-08-20 17:20:12
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\(\mathcal{Description}\) Link. 定义有向图 \(G=(V,E)\)，\(|V|=n\)，\(\lang u,v\rang \in E \Leftrightarrow u<v\)。求一个对 \(E\) 的染色 \(f\)，使得 \(\not\exist \lang v_ ...
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2021-10-20 21:21:00
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bi钱，现在要凑齐p点经验和q钱，至少要工作多久，工作的时间可以为小数思路：仔细想想总觉得哪里不对劲，是不是感觉好像只需要1份工作或者2份工作的组合就能形成最优的？事实就是这样的，想达到最优最多只需要选择2份工作就行了，那么问题就是怎么枚举出这2份工作。现在我们考虑单位时间内能完成的内容我们假设向量V1
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2022-11-24 00:02:51
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“我不想谈论广告的好坏，我只是想一心一意为应用和用户做出一流的广告”95
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2012-06-20 14:05:22
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给一个n≤1000n\le 1000n≤1000个点有向完全图(iii向jjj连边,i<ji<ji<j)求一个合法边染
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2021-10-19 20:41:38
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给(1 ≤ n ≤ 100 000 )个向量(ai,
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2015-12-14 22:48:23
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Freelancer's Dreams 我们把每个二元组看成是平面上的一个点， 那么两个点的线性组合是两点之间的连线， 即x * (a1, b1) + y * (a1, b1) && x + y == 1， 那么n个点的线性组合就是一个凸包， 那么我们求出凸包和(0, 0)到(p, q)直线的交的那
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2019-03-03 14:30:00
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QCN9074 Dreams of future connectivity with X86 systems - Super Federation
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2023-10-31 10:05:47
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C. Freelancer's DreamsTime Limit: 20 SecMemory Limit: 256 MB题目连接http://www.codeforces.com/contest/605/problem/CDescriptionMikhail the Freelancer dream...
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2021-07-15 16:24:11
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题目链接：点击打开链接思路：显然就是问最大权闭合图 和 能取最多的正点权个数1、首先对于正权值的付出，直接取，而对于梦想也忽略正权值的付出，这样就转成一个裸的最大权闭合图了。2、计算此时的正点权个数：把所有点权*大数C，然后把正点权值+1，跑出来流量就是 flow / C, 最多的正点权个数就是 正点权点集-flow%C.#include #include #inc
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2021-08-13 13:47:22
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捷克科学院有机化学与生物化学研究所研究团队，借鉴了 GPT 系列在语言领域取得的突破性进展，从全球天然产物社交分子网络（GNPS）中挖掘出 7 亿条 MS/MS 谱图，成功构建起史上规模最大的质谱数据集 GeMS，并训练出拥有 1.16 亿参数的 Transformer 模型 DreaMS。
Welcome to Hollywood!
What's your dream?
Everybody comes here,
this is Hollywood,
land of dreams.
Some dreams come true,
some don't -
but keep on dreaming.
This is Hollywood,
always t
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2007-04-22 13:42:00
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Problem DescriptionTanBig, a friend of Mr. Frog, likes eating very much, so he always has dreams about eating. One day, TanBig dreams of a field of coconuts, and the field l
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2022-07-08 10:12:32
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