a letter and a number



3000 ms  |  内存限制： 65535



1



we define f(A) = 1, f(a) = -1, f(B) = 2, f(b) = -2, ... f(Z) = 26, f(z) = -26;

Give you a letter x and a number y , you should output the result of y+f(x).


On the first line, contains a number T(0<T<=10000).then T lines follow, each line is a case.each case contains a letter x and a number y(0<=y<1000). 输出 for each case, you should the result of y+f(x) on a line 样例输入

6 R 1 P 2 G 3 r 1 p 2 g 3

样例输出

19 18 10 -17 -14 -4


# include<stdio.h>

int main()
{
  int T,y;
  char x;
  scanf("%d",&T);
  while(T--)
  {
    getchar();
    scanf("%c %d",&x,&y);
    if(x>='a' && x<='z')
      printf("%d\n",96-x+y);
    else if(x>='A' && x<='Z')
      printf("%d\n",x-64+y);
  }

  return 0;
}