请实现一个函数，把字符串中的每个空格替换成“％20”。例如输入“we are happy.”，则输出“we%20are%20happy.”
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
int main()
{
char arr[] = "we are happy";
int i = 0;
int j = 0;
int len = 0;
int count = 0;
len = strlen(arr);
for (i = 0; i < len; i++)
{
if (arr[i] == ' ')
{
count++;
}
}
i = len;
j = 2 * count + len;
while (i != j != 0)
{
if (arr[i] == ' ')
{
arr[j--] = '0';
arr[j--] = '2';
arr[j--] = '%';
i--;
}
else
{
arr[j] = arr[i];
j--;
i--;
}
}
len = strlen(arr);
for (i = 0; i < len; i++)
{
printf("%c", arr[i]);
}
printf("\n");
system("pause");
return 0;
}we%20are%20happy
请按任意键继续. . .
