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VS2005 TreeView的checkBox的父子节点级联状态
非常感谢原作者
--------
解决原有TreeView 的 CheckBox 被点击时不能引发服务器端事件
实现当TreeView中父节点的CheckBox的点选状态改变时
回发服务器端
触发TreeView1_TreeNodeCheckChanged(object sender, TreeNodeEventArgs e)事件
从而通过代码来控制子节点的CheckBox的点选状态 一同改变
主要步骤及代码示例如下：
1.TreeView绑定onclick事件
  通过本事件 引发回发
2.在TreeView1_TreeNodeCheckChanged(object sender, TreeNodeEventArgs e)事件
  编写相关代码 控制子节点的CheckBox点选状态
-------------------- HTML 页面部分 -----------------------
<html>
<head runat="server">
<title>VS2005 TreeView CheckBox</title>
<script type="text/javascript">
// 点击复选框时触发事件
function postBackByObject()
{
    var o = window.event.srcElement;
    if (o.tagName == "INPUT" && o.type == "checkbox")
  {
    __doPostBack("","");
                 }
         }
</script>
</head>
<body>
         <form id="form1" runat="server">
         <div>
                 <asp:TreeView ID="TreeView1" runat="server" OnTreeNodeCheckChanged="TreeView1_TreeNodeCheckChanged">
                         <SelectedNodeStyle BackColor="SlateGray" />                    
             </asp:TreeView>        
         </div>
         </form>
</body>
</html>


--------------------- cs页面代码 --------------------

protected void Page_Load(object sender, EventArgs e)
{
                 if (!IsPostBack)
                {
                         //构建TreeView
                            TreeNode Node00 = new TreeNode("00", "00");

                         TreeNode Node01 = new TreeNode("01", "01");
                         TreeNode Node0101 = new TreeNode("0101", "0101");
                        TreeNode Node0102 = new TreeNode("0102", "0102");
                         TreeNode Node02 = new TreeNode("02", "02");

                        Node01.ChildNodes.Add(Node0101);
                         Node01.ChildNodes.Add(Node0102);

                         Node00.ChildNodes.Add(Node01);
                        Node00.ChildNodes.Add(Node02);

                         TreeView1.Nodes.Add(Node00);

                        TreeView1.ShowCheckBoxes = TreeNodeTypes.All;//显示CheckBox
                        
                         TreeView1.ExpandDepth = 0;

                 }
                //绑定事件
                TreeView1.Attributes.Add("onclick", "postBackByObject()");

     }
        //
protected void TreeView1_TreeNodeCheckChanged(object sender, TreeNodeEventArgs e)
{
                SetChildChecked(e.Node);
}

        //
private void SetChildChecked(TreeNode parentNode)
{
                foreach (TreeNode node in parentNode.ChildNodes)
             {
                        node.Checked = parentNode.Checked;

                        if (node.ChildNodes.Count > 0)
                        {
                             SetChildChecked(node);
                        }
                }
}

转自：http://blog.csai.cn/user1/16660/archives/2008/21854.html