distinct
For example,
[1,2,3]
have the following permutations:
[ [1,2,3], [1,3,2], [2,1,3], [2,3,1], [3,1,2], [3,2,1] ]
answer:
class Solution {
public:
vector<vector<int>> permute(vector<int>& nums) {
int length = nums.size();
vector<vector<int>> result1,result2;
vector<int> temp;
result1.push_back(temp);
bool flag = false;
for(int i = 0; i < length; i ++){
for(int k = 0;k < length; k ++){
for(int j = 0; j < result1.size(); j ++){
flag = false;
temp = result1[j];
for(int l = 0; l < temp.size(); l ++){
if(temp[l] == nums[k]){
flag = true;
break;
}
}
if(flag) continue;
temp.push_back(nums[k]);
result2.push_back(temp);
temp.pop_back();
}
}
result1 = result2;
result2.clear();
}
return result1;
}
};