弄一个优先队列，每次取出最小的，然后和s时间比较，加上t时间就是答案。。。。简单贪心
#include <iostream>
#include <queue>
#include <stack>
#include <map>
#include <set>
#include <bitset>
#include <cstdio>
#include <algorithm>
#include <cstring>
#include <climits>
#include <cstdlib>
#include <cmath>
#include <time.h>
#define maxn 1000005
#define maxm 2000005
#define eps 1e-9
#define mod 1000000007
#define INF 0x3f3f3f3f
#define PI (acos(-1.0))
#define lowbit(x) (x&(-x))
#define mp make_pair
#define ls o<<1
#define rs o<<1 | 1
#define lson o<<1, L, mid
#define rson o<<1 | 1, mid+1, R
#define pii pair<int, int>
#pragma comment(linker, "/STACK:16777216")
typedef long long LL;
typedef unsigned long long ULL;
using namespace std;
LL qpow(LL a, LL b){LL res=1,base=a;while(b){if(b%2)res=res*base;base=base*base;b/=2;}return res;}
LL powmod(LL a, LL b){LL res=1,base=a;while(b){if(b%2)res=res*base%mod;base=base*base%mod;b/=2;}return res;}
//head
priority_queue<LL, vector<LL>, greater<LL> > q;
int n, m;
void read()
{
scanf("%d%d", &n, &m);
}
void work()
{
LL s, t;
for(int i = 1; i <= m; i++) q.push(0);
for(int i = 1; i <= n; i++) {
scanf("%I64d%I64d", &s, &t);
LL tt = q.top();
q.pop();
tt = max(tt, s);
tt += t;
printf("%I64d\n", tt);
q.push(tt);
}
}
int main()
{
read();
work();
return 0;
}
