A. Next Round
http://codeforces.com/problemset/problem/158/A
time limit per test
memory limit per test
input
output
k-th place finisher's score will advance to the next round, as long as the contestant earns a positive score..." — an excerpt from contest rules.
n participants took part in the contest (n ≥ k), and you already know their scores. Calculate how many participants will advance to the next round.
Input
n and k (1 ≤ k ≤ n ≤ 50) separated by a single space.
n space-separated integers a1, a2, ..., an (0 ≤ ai ≤ 100), where ai is the score earned by the participant who got the i-th place. The given sequence is non-increasing (that is, for all i from 1 to n - 1 the following condition is fulfilled: ai ≥ ai + 1).
Output
Output the number of participants who advance to the next round.
Sample test(s)
input
8 5 10 9 8 7 7 7 5 5
output
6
input
4 2 0 0 0 0
output
0
Note
In the first example the participant on the 5th place earned 7 points. As the participant on the 6th place also earned 7 points, there are 6 advancers.
In the second example nobody got a positive score.
注意特判。
完整代码:
/*30ms,0KB*/
#include<cstdio>
int main()
{
int n, k, a, i, now;
scanf("%d%d", &n, &k);
for (i = 1; i <= n; ++i)
{
scanf("%d", &a);
if (a == 0)
{
printf("%d", i - 1);
return 0;
}
if (i == k)
{
now = a;
}
else if (i > k)
{
if (a != now)
{
printf("%d", i - 1);
return 0;
}
}
}
printf("%d", i - 1);
return 0;
}