pandas 读取xlsx文件复制文件
import os
import shutil
import pandas as pd
def read_excel_and_copy_files(excel_path, files_directory, destination_directory):
# 使用pandas加载Excel文件
df = pd.read_excel(excel_path, header=None) # 不使用默认的header行
# 获取I列的所有内容，并与B列内容进行匹配
for idx, row in df.iterrows():
if idx >= 2 and pd.notnull(row[8]): # 从第3行开始读取，索引从0开始
file_name = row[8] # I列对应索引8
category = row[1] # B列对应索引1
# 如果category为空，将其设置为'other'
if pd.isnull(category):
category = 'other'
# 遍历文件目录，查找匹配的文件
file_found = False
for root, dirs, files in os.walk(files_directory):
if file_name in files:
file_found = True
folder_name = os.path.basename(root)
# 构建目标路径
target_directory = os.path.join(destination_directory, category, folder_name)
os.makedirs(target_directory, exist_ok=True)
# 复制当前文件夹中的所有文件（排除 .rar 文件）
for file in files:
if not file.endswith('.rar'):
source_file = os.path.join(root, file)
target_file = os.path.join(target_directory, file)
shutil.copy2(source_file, target_file)
print(f"复制文件 {file} 到 {target_file}")
break # 找到文件后退出循环
# 如果没有找到文件，输出错误信息
if not file_found:
print(f"文件 {file_name} 未找到")
if __name__ == "__main__":
excel_path = rf"E:\programs\read_xlsx\chenghui.xlsx" # Excel文件路径
files_directory = rf"E:\programs\read_xlsx\bd" # 要匹配文件的目录
destination_directory = rf"E:\programs\read_xlsx\new" # 自定义路径
read_excel_and_copy_files(excel_path, files_directory, destination_directory)
只复制文件
import os
import shutil
from openpyxl import load_workbook
def read_excel_and_copy_files(excel_path, files_directory, destination_directory):
# 加载Excel文件
wb = load_workbook(excel_path)
ws = wb.active
# 获取I列的所有内容，并与B列内容进行匹配
for idx, row in enumerate(ws.iter_rows(min_row=3, max_col=9, min_col=9, values_only=True), start=3):
if row[0] is not None:
file_name = row[0]
category = ws[f"B{idx}"].value
# 遍历文件目录，查找匹配的文件
for root, dirs, files in os.walk(files_directory):
if file_name in files:
source_file = os.path.join(root, file_name)
# 构建目标路径
target_directory = os.path.join(destination_directory, category)
os.makedirs(target_directory, exist_ok=True)
target_file = os.path.join(target_directory, file_name)
# 复制文件
shutil.copy2(source_file, target_file)
print(f"复制文件 {file_name} 到 {target_file}")
break # 找到文件后退出循环
if __name__ == "__main__":
excel_path = rf"E:\programs\read_xlsx\chenghui.xlsx" # Excel文件路径
files_directory = rf"E:\programs\read_xlsx\bd" # 要匹配文件的目录
destination_directory = rf"E:\programs\read_xlsx\new" # 自定义路径
read_excel_and_copy_files(excel_path, files_directory, destination_directory)
升级完善版本
"""
filename：
program：requirement
author：
dater：2024/07/10
-----------------------
"""
import os
import shutil
from openpyxl import load_workbook
def read_excel_and_copy_files(excel_path, files_directory, destination_directory):
# 加载Excel文件
wb = load_workbook(excel_path)
ws = wb.active
# 获取I列的所有内容，并与B列内容进行匹配
for idx, row in enumerate(ws.iter_rows(min_col=9, max_col=9, min_row=3, values_only=True), start=3):
if row[0] is not None:
file_name = row[0]
category = ws[f"B{idx}"].value
# 如果category为空，将其设置为'other'
if not category:
category = 'other'
# 遍历文件目录，查找匹配的文件
file_found = False
for root, dirs, files in os.walk(files_directory):
if file_name in files:
file_found = True
folder_name = os.path.basename(root)
# 构建目标路径
target_directory = os.path.join(destination_directory, category, folder_name)
os.makedirs(target_directory, exist_ok=True)
# 复制当前文件夹中的所有文件（排除 .rar 文件）
for file in files:
if not file.endswith('.rar'):
source_file = os.path.join(root, file)
target_file = os.path.join(target_directory, file)
shutil.copy2(source_file, target_file)
print(f"复制文件 {file} 到 {target_file}")
break # 找到文件后退出循环
# 如果没有找到文件，输出错误信息
if not file_found:
print(f"文件 {file_name} 未找到")
if __name__ == "__main__":
excel_path = rf"E:\programs\read_xlsx\chenghui.xlsx" # Excel文件路径
files_directory = rf"E:\programs\read_xlsx\bd" # 要匹配文件的目录
destination_directory = rf"E:\programs\read_xlsx\new" # 自定义路径
read_excel_and_copy_files(excel_path, files_directory, destination_directory)
