Java HttpResponse 获取信息

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mob64ca12e1c36d 2024-06-21 07:25:33 ©著作权

文章标签 java apache System 文章分类 Java 后端开发

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实现Java HttpResponse 获取信息

1. 流程图

flowchart TD
    Start --> 创建HttpClient对象
    创建HttpClient对象 --> 创建HttpGet对象
    创建HttpGet对象 --> 发送请求
    发送请求 --> 获取HttpResponse对象
    获取HttpResponse对象 --> 处理HttpResponse对象
    处理HttpResponse对象 --> End

2. 整体流程

首先，我们需要创建一个HttpClient对象，然后创建一个HttpGet对象，发送请求并获取HttpResponse对象，最后处理HttpResponse对象中的信息。

3. 详细步骤

创建HttpClient对象

// 创建HttpClient对象
CloseableHttpClient httpClient = HttpClients.createDefault();

创建HttpGet对象

// 创建HttpGet对象
HttpGet httpGet = new HttpGet("

发送请求并获取HttpResponse对象

// 发送请求并获取HttpResponse对象
CloseableHttpResponse httpResponse = httpClient.execute(httpGet);

处理HttpResponse对象

// 获取状态码
int statusCode = httpResponse.getStatusLine().getStatusCode();
System.out.println("Status Code: " + statusCode);
// 获取响应内容
HttpEntity httpEntity = httpResponse.getEntity();
String response = EntityUtils.toString(httpEntity);
System.out.println("Response: " + response);

4. 完整代码示例

import org.apache.http.client.methods.CloseableHttpResponse;
import org.apache.http.client.methods.HttpGet;
import org.apache.http.impl.client.CloseableHttpClient;
import org.apache.http.impl.client.HttpClients;
import org.apache.http.util.EntityUtils;

public class Main {
    public static void main(String[] args) throws IOException {
        // 创建HttpClient对象
        CloseableHttpClient httpClient = HttpClients.createDefault();

        // 创建HttpGet对象
        HttpGet httpGet = new HttpGet("

        // 发送请求并获取HttpResponse对象
        CloseableHttpResponse httpResponse = httpClient.execute(httpGet);

        // 获取状态码
        int statusCode = httpResponse.getStatusLine().getStatusCode();
        System.out.println("Status Code: " + statusCode);

        // 获取响应内容
        HttpEntity httpEntity = httpResponse.getEntity();
        String response = EntityUtils.toString(httpEntity);
        System.out.println("Response: " + response);
    }
}