小记:熟练了下prim,其实是照着dijsktra来写的,就一个判断条件的不同而已


思路:prim算法


代码:

#include <iostream>
#include <stdio.h>
#include <string.h>
#include <math.h>
#include <stdlib.h>
#include <map>
#include <set>
#include <vector>
#include <stack>
#include <queue>
#include <algorithm>
#include <string>

using namespace std;

#define mst(a,b) memset(a,b,sizeof(a))
#define REP(a,b,c) for(int a = b; a < c; ++a)
#define eps 10e-8

const int MAX_ = 155;
const int N = 100010;
const int INF = 0x7fffffff;

int n;

struct node{
    int s, t;
};

int g[MAX_][MAX_];
int d[MAX_];
bool vis[MAX_];
int m, cnt;

int prim(int start)
{
    REP(i, 0, n){
        d[i] = INF;
        vis[i] = 0;
    }
    int sum = 0;
    d[start] = 0;

    REP(i, 0, n){
        int mmin = INF, k;
        REP(j, 0, n){
            if(!vis[j] && d[j] < mmin){
                mmin = d[j];
                k = j;
            }
        }
        vis[k]  = 1;
        sum += mmin;
        REP(j, 0, n){
            if(!vis[j]  && d[j] > g[k][j]){
                d[j] = g[k][j];
            }
        }
    }
    return sum;
}

int main(){
	int T, ss, tt;

	while(~scanf("%d", &n)){

        REP(i, 0, n)REP(j, 0, n){
            scanf("%d", &g[i][j]);
        }

        int ans = prim(0);

        printf("%d\n", ans);

	}
	return 0;
}