49. Group Anagrams刷题笔记

复杂度为n的三次方，勉强过

class Solution:
    def groupAnagrams(self, strs: List[str]) -> List[List[str]]:
        result = []
        hashMap = []
        for string in strs:
            tmpHash = [0]*26
            for i in range(len(string)):
                tmpHash[ord(string[i])-ord('a')] += 1
            if tmpHash in hashMap:
                result[hashMap.index(tmpHash)].append(string)
            else:
                hashMap.append(tmpHash)
                result.append([string])
        return result