题目描述
总体说明
考生需要模拟实现一个简单的自动售货系统,实现投币、购买商品、退币、查询库存商品及存钱盒信息的功能。
系统初始化时自动售货机中商品为6种商品,商品的单价自定义,存钱盒内放置1元、2元、5元、10元钱币,商品数量和钱币张数通过初始化命令设置。
商品:每种商品包含商品名称、单价、数量三种属性,其中商品名不重复。不能修改商品名称和单价,初始化命令设置商品数量。
choice = input("""请输入你需要的业务:
1).购买商品;
2).管理员查询
输入:""")
num_kele = 10
num_pijiu = 10
num_naicha = 10
num_kuangquanshui = 10
num_kafei = 10
num_niunai = 10
shiyuan = 100
wuyuan = 100
liangyuan = 100
yiyuan = 100
while True :
if choice == '1' :
print (""" 你好,有如下商品可供你选择:
1).可乐 2).啤酒 3).奶茶
4).矿泉水 5).咖啡 6).牛奶
""")
choice = input("请输入你要购买商品的序号:")
if choice == '1' :
num = int(input("你好,可乐一瓶三元,请输入你要购买的数量:"))
if num <= num_kele :
print ("你好,一共%s元。" %(num * 3 ))
money = int(input("请将钞票放入入钞口:"))
while True :
if money == (num * 3):
num_kele -= num
print("购买成功,欢迎下次光临!")
break
elif money > (num * 3):
num1 = money - (num * 3)
for i in range(yiyuan + 1):
for j in range(liangyuan + 1):
for o in range(wuyuan + 1):
for p in range(shiyuan + 1):
if p * 10 + o * 5 + j * 2 + i * 1 == num1:
print("购买成功,一共找你%s元" %(num1))
shiyuan -= p
wuyuan -= o
liangyuan -= j
yiyuan -= i
exit(0)
elif money < (num*3) :
money = int(input("请继续投入现金")) + money
if num > num_kele :
print ("抱歉,数量不够,请重新输入你要购买的数量!")
elif choice == '2' :
num = int(input("你好,啤酒一瓶四元,请输入你要购买的数量:"))
if num <= num_pijiu :
print ("你好,一共%s元。" %(num * 4 ))
money = int(input("请将钞票放入入钞口:"))
if money == (num * 4):
num_pijiu -= num
print("购买成功,欢迎下次光临!")
elif money < (num * 4):
num = int(input("请继续投入现金:")) + money
elif money > (num * 4):
num1 = money - (num * 4)
for i in range(yiyuan + 1):
for j in range(liangyuan + 1):
for o in range(wuyuan + 1):
for p in range(shiyuan + 1):
if p * 10 + o * 5 + j * 2 + i * 1 == num1:
print("购买成功,一共找你%s元" %(num1))
shiyuan -= p
wuyuan -= o
liangyuan -= j
yiyuan -= i
exit(0)
if num > num_pijiu :
print ("抱歉,数量不够,请重新输入你要购买的数量!")
elif choice == '3' :
num = int(input("你好,奶茶一瓶五元,请输入你要购买的数量:"))
if num <= num_naicha :
print ("你好,一共%s元。" %(num * 5 ))
money = int(input("请将钞票放入入钞口:"))
if money == (num * 5):
num_naicha -= num
print("购买成功,欢迎下次光临!")
elif money < (num * 5):
num = int(input("请继续投入现金:")) + money
elif money > (num * 5):
num1 = money - (num * 5)
for i in range(yiyuan + 1):
for j in range(liangyuan + 1):
for o in range(wuyuan + 1):
for p in range(shiyuan + 1):
if p * 10 + o * 5 + j * 2 + i * 1 == num1:
print("购买成功,一共找你%s元" % (num1))
shiyuan -= p
wuyuan -= o
liangyuan -= j
yiyuan -= i
exit(0)
if num > num_naicha :
print ("抱歉,数量不够,请重新输入你要购买的数量!")
elif choice == '4' :
num = int(input("你好,矿泉水一瓶两元,请输入你要购买的数量:"))
if num <= num_kuangquanshui :
print ("你好,一共%s元。" %(num * 2 ))
money = int(input("请将钞票放入入钞口:"))
if money == (num * 2):
num_kuangquanshui -= num
print("购买成功,欢迎下次光临!")
elif money < (num * 2):
num = int(input("请继续投入现金:")) + money
elif money > (num * 2):
num1 = money - (num * 2)
for i in range(yiyuan + 1):
for j in range(liangyuan + 1):
for o in range(wuyuan + 1):
for p in range(shiyuan + 1):
if p * 10 + o * 5 + j * 2 + i * 1 == num1:
print("购买成功,一共找你%s元" % (num1))
shiyuan -= p
wuyuan -= o
liangyuan -= j
yiyuan -= i
exit(0)
if num > num_kuangquanshui :
print ("抱歉,数量不够,请重新输入你要购买的数量!")
elif choice == '5' :
num = int(input("你好,咖啡一瓶六元,请输入你要购买的数量:"))
if num <= num_kafei :
print ("你好,一共%s元。" %(num * 6 ))
money = int(input("请将钞票放入入钞口:"))
if money == (num * 6):
num_kafei -= num
print("购买成功,欢迎下次光临!")
elif money < (num * 6):
num = int(input("请继续投入现金:")) + money
elif money > (num * 6):
num1 = money - (num * 6)
for i in range(yiyuan + 1):
for j in range(liangyuan + 1):
for o in range(wuyuan + 1):
for p in range(shiyuan + 1):
if p * 10 + o * 5 + j * 2 + i * 1 == num1:
print("购买成功,一共找你%s元" % (num1))
shiyuan -= p
wuyuan -= o
liangyuan -= j
yiyuan -= i
exit(0)
if num > num_kafei :
print ("抱歉,数量不够,请重新输入你要购买的数量!")
elif choice == '6' :
num = int(input("你好,牛奶一瓶五元,请输入你要购买的数量:"))
if num <= num_niunai :
print ("你好,一共%s元。" %(num * 5 ))
money = int(input("请将钞票放入入钞口:"))
if money == (num * 5):
num_niunai -= num
print("购买成功,欢迎下次光临!")
elif money < (num * 5):
num = int(input("请继续投入现金:")) + money
elif money > (num * 5):
num1 = money - (num * 5)
for i in range(yiyuan + 1):
for j in range(liangyuan + 1):
for o in range(wuyuan + 1):
for p in range(shiyuan + 1):
if p * 10 + o * 5 + j * 2 + i * 1 == num1:
print("购买成功,一共找你%s元" % (num1))
shiyuan -= p
wuyuan -= o
liangyuan -= j
yiyuan -= i
exit(0)
if num > num_niunai :
print ("抱歉,数量不够,请重新输入你要购买的数量!")
else :
print("对不起,没有该商品!请重新输入!")
if choice == '2' :
X = input("""请输入你要查询的信息:
1).商品库存;
2).存钱盒信息
3).退出
请输入你需要的信息:""")
if X == '1' :
print ('可乐%s瓶,啤酒%s瓶,奶茶%s瓶,矿泉水%s瓶,咖啡%s瓶,牛奶%s瓶' %(num_kele,num_pijiu,num_naicha,num_kuangquanshui,num_kafei,num_niunai))
if X == '2' :
shiyuan = 100
wuyuan = 100
liangyuan = 100
yiyuan = 100
print ("十元%s张,五元%s张,两元%s张,一元%s张" %(shiyuan,wuyuan,liangyuan,yiyuan))
if X == '3' :
break
--end