题目：

Given an array nums, write a function to move all 0's to the end of it while maintaining the relative order of the non-zero elements.

For example, given nums = [0, 1, 0, 3, 12], after calling your function, nums should be [1, 3, 12, 0, 0].

Note:

  1. You must do this in-place without making a copy of the array.
  2. Minimize the total number of operations.
思路：

本题有个简单明了的思路，维护一个变量count ，遍历一次数组，在遍历的同时判断数值是否为0，为0，count++，并将0删除，最后在数组末尾添上对应个数的0即可

代码：

class Solution {
public:
    void moveZeroes(vector<int>& nums) {
        vector<int>::iterator itr=nums.begin();
        int count =0;
        while(1)
        {
            if(itr==nums.end())
                break;
            if(*itr==0)
            {
                count++;
                nums.erase(itr); 
                continue;
            }
            itr++;
        }
        for(int j=0;j<count;j++)
            nums.push_back(0);
        
    }
};