create table testA(
id int primary key,
Name varchar(10)
);
insert into testA values(1, '小黄');
insert into testA values(2, '小绿');
insert into testA values(3, '小白');
insert into testA values(4, '小黑');
insert into testA values(5, '小花');
commit;

create table testB(
id int primary key,
age int(10)
);
insert into testB values(1, 10);
insert into testB values(2, 11);
insert into testB values(3, 12);
insert into testB values(4, 13);

内连接

select * from testA t1 inner join testB t2 on t1.id=t2.id and t1.name='小白';

left join on 后跟and和where区别_结果集

select * from testA t1 inner join testB t2 on t1.id=t2.id  where t1.name='小白';

left join on 后跟and和where区别_结果集_02

 左连接

select * from testA t1 left join testB t2 on t1.id=t2.id and t1.name='小白';

left join on 后跟and和where区别_外连接_03

select * from testA t1 left join testB t2 on t1.id=t2.id  where t1.name='小白';

left join on 后跟and和where区别_外连接_04

其实以上结果的关键原因就是1eft join,right join,fulljoin的特殊性,不管on上的条件是否为真都会返回1eft或right表中的记录,ful1则具有1eft和right的特性的并集。而inner join 没这个特殊性,则条件放在on中和where中,返回的结果集是相同的。on为了反映外连接中一方的全连接,而where没有这个功能,内连接配对是可以的。