搞个竖着的前缀和然后枚举连续的行做尺取就可以了,水题

#include <bits/stdc++.h>
using namespace std;
const int INF = 0x3f3f3f3f;
int n, a[150][150], sum[150][150], b[150], ans;
void solve() {
int sum = 0;
for (int l = 1, r = 1; r <= n; r++) {
sum += b[r];
while (sum < 0 && l <= r) sum -= b[l++];
ans = max(ans, sum);
}
}
int main() {
while (~scanf("%d", &n)) {
memset(sum, 0, sizeof(sum));
for (int i = 1; i <= n; i++) {
for (int j = 1; j <= n; j++) {
scanf("%d", &a[i][j]);
sum[i][j] = sum[i-1][j] + a[i][j];
}
}
ans = -INF;
for (int k = 1; k <= n; k++) {
for (int s = 1; s+k-1 <= n; s++) {
int t = s+k-1;
for (int j = 1; j <= n; j++) {
b[j] = sum[t][j] - sum[s-1][j];
}
solve();
}
}
printf("%d\n", ans);
}
return 0;
}