HDOJ2113 Secret Number

题目链接：​​Secret Number​​

计算出给定数各个位上数字为偶数的和。题目说明了在int范围里了。

只要每一位都判断一下是否%2==0

import java.util.Scanner;

public class Main{
  private static Scanner scanner;

  public static void main(String[] args) {
    scanner = new Scanner(System.in);
    boolean boo = false;
    while(scanner.hasNext()){
      if(boo){
        System.out.println();
      }
      int n = scanner.nextInt();
      int sum = 0;
      while(n!=0){
        if((n%10)%2 == 0){//如果是偶数
          sum+= n%10;
        }
        n /= 10;
      }
      System.out.println(sum);
      boo = true;
    }
  }
}