Guess the number


Time Limit: 1000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 4869    Accepted Submission(s): 3575


Problem Description


Happy new year to everybody!
Now, I want you to guess a minimum number x betwwn 1000 and 9999 to let
(1) x % a = 0;
(2) (x+1) % b = 0;
(3) (x+2) % c = 0;
and a, b, c are integers between 1 and 100.
Given a,b,c, tell me what is the number of x ?


 



Input


The number of test cases c is in the first line of input, then c test cases followed.every test contains three integers a, b, c.


 



Output


For each test case your program should output one line with the minimal number x, you should remember that x is between 1000 and 9999. If there is no answer for x, output "Impossible".


 



Sample Input


2 44 38 49 25 56 3


 



Sample Output


Impossible 2575


题目给定了范围，加个for循环直接暴力解决问题 

import java.util.Scanner;

//x is between 1000 and 9999
public class Main{
  private static Scanner scanner;

  public static void main(String[] args) {
    scanner = new Scanner(System.in);
    int cases = scanner.nextInt();
    HH:while(cases-->0){
      int a = scanner.nextInt();
      int b = scanner.nextInt();
      int c = scanner.nextInt();
      
      for (int x = 1000; x <= 9999; x++) {
        if(x%a==0 && (x+1)%b==0 && (x+2)%c==0){
          System.out.println(x);
          continue HH;//使用label
        }
      }
      System.out.println("Impossible");
    }
  }
}