函数之 1000-2000年之间的闰年年份

#include<stdio.h>

int is_leap_year(int y)

{

if (y % 4 == 0 && y % 100 != 0 || y % 400 == 0)

{

 return 1;

}

else

return 0;

}

int main()

{

int year = 0;

for (year = 1000; year <= 2000; year++)

{

 if (is_leap_year(year) == 1)

  printf("%d is leap year\n", year);

}

return 0;

}