C# 启动进程

System.Diagnostics.ProcessStartInfo psi = new System.Diagnostics.ProcessStartInfo(filename);
                        psi.WindowStyle = System.Diagnostics.ProcessWindowStyle.Normal;
                        psi.UseShellExecute = true;
                        psi.Arguments = string.Format("\"{0}\" \"{1}\" \"{2}\"", arg, strTableName, timeOut);
                        System.Diagnostics.Process listFiles;
                        listFiles = System.Diagnostics.Process.Start(psi);
                        Application.DoEvents();
                        listFiles.WaitForExit();