题目:原题链接(中等)
标签:哈希表
解法 | 时间复杂度 | 空间复杂度 | 执行用时 |
Ans 1 (Python) | O ( N ) : N为砖块总数 | O ( N ) | 204ms (94.75%) |
Ans 2 (Python) | |||
Ans 3 (Python) |
解法一:
class Solution:
def leastBricks(self, wall: List[List[int]]) -> int:
total = len(wall)
interval = collections.Counter()
for w in wall:
now = 0
for n in w[:-1]:
now += n
interval[now] += 1
ans = interval.most_common(1)
return total - (ans[0][1] if ans else 0)