按字典序输出所有在123..n之间插入'+','-',' '结果为0的表达式。.
http://train.usaco.org/usacoprob2?a=jUh88pMwCSQ&S=zerosum
/* TASK:zerosum LANG:C++ */ #include<cstdio> #include<string> #include<algorithm> using namespace std; #define N 15 int n; int k[N],cnt,s[3]={0,1,-1}; string ans[7000]; void dfs(int d){ if(d>n){ int sum=0,c=1; for(int i=2;i<=n;i++){ if(k[i]){ sum+=c; c=i*k[i]; }else{ c=c*10+(c>0?i:-i); } } sum+=c; if(sum==0){ ans[++cnt]+="1"; for(int i=2;i<=n;i++){ ans[cnt]+=k[i]>0?'+':k[i]<0?'-':' '; ans[cnt]+=i+'0'; } } return; } for(int i=0;i<=2;i++){ k[d]=s[i]; dfs(d+1); } } int main(){ freopen("zerosum.in","r",stdin); freopen("zerosum.out","w",stdout); scanf("%d",&n); dfs(2); for(int i=1;i<=cnt;i++){ printf("%s\n",ans[i].c_str()); } }
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