Problem A. Alien Communication Masterclass

Time Limit: 1 Sec  

Memory Limit: 256 MB

题目连接

http://codeforces.com/gym/100610

Description

Andrea is a famous science fiction writer, who runs masterclasses for her beloved readers. The most popular one is the Alien Communication Masterclass (ACM), where she teaches how to behave if you encounter alien life forms or at least alien artifacts. One of the lectures concerns retrieving useful information based on aliens’ writings. Andrea teaches that based on alien mathematical formulas, one could derive the base of the numeral system used by the aliens, which in turn might give some knowledge about aliens’ organisms. (For example, we use numeral system with base 10, due to the fact that we have ten fingers on our upper extremities). Suppose for simplicity that aliens use the same digits as we do, and they understand and denote addition, subtraction, multiplication, parentheses and equality the same way as we do. For her lecture, Andrea wants an example of a mathematical equality that holds in numeral systems with bases a1, a2, · · · , an, but doesn’t hold in numeral systems with bases b1, b2, · · · , bm. Provide her with one such formula.

Input

The first line of the input file contains two integer numbers, n and m (1 ≤ n, m ≤ 8). The second line contains n numbers, a1, a2, · · · , an. The third line contains m numbers, b1, b2, · · · , bm. All ai and bi are distinct and lie between 2 and 10, inclusive.

Output

Output any syntactically correct mathematical equality that holds in numeral systems with bases a1, a2, · · · , an, but doesn’t hold in numeral systems with bases b1, b2, · · · , bm. The equality can contain only digits 0 through 9, addition (‘+’), subtraction and unary negation (‘-’), multiplication (‘*’), parentheses (‘(’ and ‘)’) and equality sign (‘=’). There must be exactly one equality sign in the output. Any whitespace characters in the output file will be ignored. The number of non-whitespace characters in the output file must not exceed 10 000.

Sample Input

1 2 2 3 9

Sample Output

(10 - 1) * (10 - 1) + 1 = 10

HINT

 

题意

要求你输出等式，满足N种进制，但是不满足任何的M种进制

题解：

直接输出(10-a1*1)*(10-a2*1)*……*(10-an*1)=0就好了

只有在n种进制中才能满足条件

代码：

//qscqesze
#include <cstdio>
#include <cmath>
#include <cstring>
#include <ctime>
#include <iostream>
#include <algorithm>
#include <set>
#include <bitset>
#include <vector>
#include <sstream>
#include <queue>
#include <typeinfo>
#include <fstream>
#include <map>
#include <stack>
typedef long long ll;
using namespace std;
//freopen("D.in","r",stdin);
//freopen("D.out","w",stdout);
#define sspeed ios_base::sync_with_stdio(0);cin.tie(0)
#define maxn 110000
#define mod 1001
#define eps 1e-9
#define pi 3.1415926
int Num;
//const int inf=0x7fffffff;   //§ß§é§à§é¨f§³
const ll inf=999999999;
inline ll read()
{
    ll x=0,f=1;char ch=getchar();
    while(ch<'0'||ch>'9'){if(ch=='-')f=-1;ch=getchar();}
    while(ch>='0'&&ch<='9'){x=x*10+ch-'0';ch=getchar();}
    return x*f;
}
//*************************************************************************************


//(k-a1)(k-a2)(k-a3)*.....*(k-an)

int a[11];
int b[11];
int main()
{
    freopen("acm.in","r",stdin);
    freopen("acm.out","w",stdout);
    int n=read(),m=read();
    for(int i=0;i<n;i++)
        cin>>a[i];
    for(int i=0;i<m;i++)
        cin>>b[i];
    for(int i=0;i<n;i++)
    {
        cout<<"(10-";
        for(int j=1;j<=a[i];j++)
        {
            if(j!=a[i])
                cout<<"1-";
            else
                cout<<"1";
        }
        if(i!=n-1)
            cout<<")*";
        else
            cout<<")";
    }
    cout<<"=0";
}