JSON.NET 简单的使用

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mob604756f828bf 2014-06-17 19:34:00

文章标签 json .net android json对象 json字符串 文章分类 .Net 后端开发

JSON.NET（http://json.codeplex.com/）使用来将.NET中的对象转换为JSON字符串（序列化？），或者将JSON字符串转换为.NET中已有类型的对象（反序列化？）

首先为了例子随便定义一个类型：

public class Product
{
    public string Name { get; set; }
    public DateTime Expiry { get; set; }
    public decimal Price { get; set; }
    public string[] Sizes { get; set; }

    public override string ToString()
    {
        return string.Format("Name:{0},Expiry:{1},Price:{2},SizesCount:{3}"
            , Name, Expiry, Price, Sizes.Length);
    }
}

初始化对象：

public static void Main(string[] passwordargs)
{
    Product product = new Product()
    {
        Name = "android",
        Expiry = DateTime.Now,
        Price = 2000,
        Sizes = new string[] { "1.5", "2.2", "4.1" }
    };
}

进行到JSON的转换：

Console.WriteLine(JsonConvert.SerializeObject(product));

输出结果：

{"Name":"android","Expiry":"2013-08-30T09:50:11.5147845+08:00","Price":2000.0,"Sizes":["1.5","2.2","4.1"]}

其它看起来一切正常，除了这个日期有点怪

格式化日期：

//设置日期时间的格式，与DataTime类型的ToString格式相同
IsoDateTimeConverter iso = new IsoDateTimeConverter();
iso.DateTimeFormat = "yyyy-MM-dd HH:mm:ss";

Console.WriteLine(JsonConvert.SerializeObject(product, iso));

输出结果：

{"Name":"android","Expiry":"2013-08-30 09:53:58","Price":2000.0,"Sizes":["1.5","2.2","4.1"]}

从JSON到对象的转换：

string str = "{\"Name\":\"android\",\"Expiry\":\"2013-08-30 09:53:58\",\"Price\":2000.0,\"Sizes\":[\"1.5\",\"2.2\",\"4.1\"]}";

Product p = (Product)JsonConvert.DeserializeObject(str, typeof(Product));

Console.WriteLine(p.ToString());

输出结果：

Name:android,Expiry:2013/8/30 9:53:58,Price:2000.0,SizesCount:3

从JSON到键值对的转换：

string strJson = @"{""Name1"": ""小明"",""Name2"": ""小花"",""Name3"": ""小红""}";

Dictionary<string, string> _dictionary = JsonConvert.DeserializeObject<Dictionary<string, string>>(strJson);

foreach (KeyValuePair<string, string> kp in _dictionary)
{
    Console.WriteLine(kp.Key + ":" + kp.Value);
}

输出结果：

Name1:小明
Name2:小花
Name3:小红

从字符串转换到JSON对象，以及JSON对象的简单使用：

string strJson2 = @"{ ""student"": { ""Name1"": ""小明"" , ""Name2"": ""小花"" , ""Name3"": ""小红""} }";

JObject jsonObj = JObject.Parse(strJson2);

Console.WriteLine(jsonObj["student"]["Name1"].ToString());
Console.WriteLine(jsonObj["student"]["Name2"].ToString());
Console.WriteLine(jsonObj["student"]["Name3"].ToString());

输出结果：

小明
小花
小红

直接生成JSON对象：

JObject json =
    new JObject(
    new JProperty("Channel",
        new JObject(
        new JProperty("title", "JSON"),
        new JProperty("link", "JSON.NET"),
        new JProperty("description", "JSON.NET Description"),
        new JProperty("items",
            new JArray(
            new JObject(new JProperty("haha1", "123")),
            new JObject(new JProperty("haha2", "456")),
            new JObject(new JProperty("haha3", "789"))
                )))));

Console.WriteLine(json.ToString());

输出结果：

{
"Channel": {
    "title": "JSON",
    "link": "JSON.NET",
    "description": "JSON.NET Description",
    "items": [
      {
        "haha1": "123"
      },
      {
        "haha2": "456"
      },
      {
        "haha3": "789"
      }
    ]
}
}