leetcode - Search for a Range

Given a sorted array of integers, find the starting and ending position of a given target value.

Your algorithm's runtime complexity must be in the order of O(log n).

If the target is not found in the array, return [-1, -1].

For example,
Given [5, 7, 7, 8, 8, 10] and target value 8,
return [3, 4].

 

class Solution {
public:
    std::vector<int> searchRange(int A[], int n, int target) {
		std::vector<int> vec;
		int i;
		int cnt = 0;
		bool t = true;
		for (i = 0; i < n; i++)
		{
			if(A[i] == target)
			{
				cnt++;
				t = false;
			}
			else if(!t)
			{
				break;
			}
		}
		if(cnt == 0)
		{
			vec.push_back(-1);
			vec.push_back(-1);
			return vec;
		}
		else
		{
			vec.push_back(i-cnt);
			vec.push_back(i-1);
			return vec;
		}
    }
};